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3 years ago

A hexagonal pyramid is cut by a plane as shown in the diagram. What is the shape of the resulting cross section? see diagram

Mathematics

2 answers:

Alenkasestr [34]3 years ago

9 0

From the diagram you can see that plane cuts each lateral face of hexagonal pyramid and do not cut the base. A hexagonal pyramid has six lateral faces. The intersection of each of these lateral faces with given cutting plane is segment. The figure which consists of these segments is hexagon. This hexagon is not the same as base and even is not similar to the base because the cutting plane is not parallel to the base.

Answer: resulting cross section is a hexagon, correct choice is option 4.

Elan Coil [88]3 years ago

4 0

Cutting a hexagonal pyramid by a plane parallel to the base would result to a cross section with a shape of hexagon which would be same with its base. A cross section is a plane that results from cutting an object using a plane.

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If n is a term of the sequence 14, 8, 2, -4, …, which expression would you give the value of n?

Ipatiy [6.2K]

Answer:

-6n+20

Step-by-step explanation:

The given term of sequece is 14, 8, 2, -4, …,

Here the first term is 14 and then the terms are decreasing by 6 each time because $14-8=8-2=...=6$

As we know that the nth term of the sequence is given by the formula

$t_n=a+(n-1)d\\\text{Substitute the values we get}\\t_n=14+(n-1)(-6)\\t_n=14-6n+6\\t_n=20-6n\\$

If n is a term of the given sequence sequence, then its value is -6n+20

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3 years ago

Which inequality is represented by this graph?

Marrrta [24]

Answer:

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2 years ago

The volume of this rectangular prism is 4x^3 (4x cubed). What does the coefficient 4 mean in terms of the problem?

yKpoI14uk [10]

It means that has four of those cubes inside one prism... it's hard to explain but x^3 is ONE CUBE not prism, YOU HAVE FOUR of them, hope this helpz

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2 years ago

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Persons having Raynaud's syndrome are apt to suffer a sudden impairment of blood circulation in fingers and toes. In an experime

Citrus2011 [14]

Answer:

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

Step-by-step explanation:

We have to perform a hypothesis test on the difference between means.

The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2$

μ1: mean heat output for subjects with the syndrome.

μ2: mean heat output for non-sufferers.

We will use a significance level of 0.05.

The difference between sample means is:

$M_d=\bar x_1-\bar x_2=0.63-2.09=-1.46$

The standard error is

$s_{M_d}=\sqrt{\sigma_1^2/n_1+\sigma_2^2/n_2}=\sqrt{0.3^2/9+0.5^2/9}=\sqrt{ 0.038 } \\\\ s_{M_d}=0.194$

The t-statistic is

$t=\dfrac{M_d}{s_{M_d}}=\dfrac{-1.46}{0.194}=-7.52$

The degrees of freedom are

$df=n_1+n_2-2=9+9-2=16$

The critical value for a left tailed test at a significance level of 0.05 and 16 degrees of freedom is t=-1.746.

The t-statistic is below the critical value, so it lies in the rejection region.

The null hypothesis is rejected.

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

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2 years ago

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Angelina_Jolie [31]

Answer:

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Step-by-step explanation:

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2 years ago

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