Assume that blood pressure readings are normally distributed with a mean of 124 and a standard deviation of 6.4. If 64 people ar
e randomly selected, find the probability that their mean blood pressure will be less than 126. Round to four decimal places.
1 answer:
Answer:
99.38%
Step-by-step explanation:
We have that the mean (m) is equal to 124, the standard deviation (sd) 6.4 and the sample size (n) = 64
They ask us for P (x <126)
For this, the first thing is to calculate z, which is given by the following equation:
z = (x - m) / (sd / (n ^ 1/2))
We have all these values, replacing we have:
z = (126 - 124) / (6.4 / (64 ^ 1/2))
z = 2.5
With the normal distribution table (attached), we have that at that value, the probability is:
P (z <2.5) = 0.9938
The probability is 99.38%
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<span>(Decimal: 217.5)
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For if its
Then is
~ Hope this helps
Answer:
∴Given Δ ABC is not a right-angle triangle
a= AB = √45 = 3√5
b = BC = 12
c = AC = √45 = 3√5
Step-by-step explanation:
Given vertices are A(3,3) and B(6,9)
AB =
Given vertices are B(6,9) and C( 6,-3)
=
BC = 12
Given vertices are A(3,3) and C( 6,-3)
AC² = AB²+BC²
45 = 45+144
45 ≠ 189
∴Given Δ ABC is not a right angle triangle