Answer:
lol it so easy man 3(y+4) is the answer
Answer:
I think 4:1 I'm not that sure tho
Answer:
The given points are

The setting would have a interval or 2 units above and below the minimum and maximum of each coordinate.
The given maxium horizontal coordinate is 0.
The given minimum horizontal coordinate is -13.
The given maximum vertical coordinate is 3.
The given minimum vertical coordinate is -7.
Now, we extend each maximum and minimum value by 2 units to create the setting.
So, the setting is

With a scale of 2 units.
Answer:
a couple of irrational numbers: -16±4√19, approximately {1.436, -33.436}
Step-by-step explanation:
Your question can be cast as the quadratic equation
x² +32x -48 = 0
The solutions can be found using the quadratic formula:
x = (-32 ±√(32² -4(1)(-48)))/(2(1)) = -16±√304 = -16±4√19
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<em>Comment on the equation we used</em>
We notice that when p and q are roots, the equation can be written ...
(x -p)(x -q) = 0 = x² -(p+q)x +pq
You want p+q = -32, pq = -48, so the equation is ...
x² -(-32)x +(-48) = 0
x² +32x -48 = 0 . . . . . . with parentheses eliminated