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Anuta_ua [19.1K]
3 years ago
10

Danielle plans to graph the linear equation 5x-2y=10 by plotting the x-intercept and y-intercept.

Mathematics
1 answer:
Darya [45]3 years ago
4 0

Answer:

see the explanation

Step-by-step explanation:

we have

5x-2y=10

<em>Find the x-intercept</em>

Remember that the x-intercept is the value of x when the value of y is equal to zero

For y=0

5x-2(0)=10\\5x=10\\x=2

the x-intercept is the point (2,0)

<em>Find the y-intercept</em>

Remember that the y-intercept is the value of y when the value of x is equal to zero

For x=0

5(0)-2y=10\\-2y=10\\y=-5

the y-intercept is the point (0,-5)

using a graphing tool

Plot the intercepts and connect them to graph the line

see the attached figure

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Dmitriy789 [7]

The answer would be 7.42

Use desmos online calculator

5 0
3 years ago
4x + 2y = 8 16x - y = 14
lys-0071 [83]
Equation 1)  4x + 2y = 8
Equation 2)  16x - y = 14

Multiply all of equation 2 by 2.

2)  2(16x - y = 14)

2)  32x - 2y = 28
1)  4x + 2y = 8

Add equations together.

36x = 36

Divide both sides by 36.

x = 1

Plug in 1 for x in the first equation.

4x + 2y = 8

4(1) + 2y = 8

4 + 2y = 8

Subtract 4 from both sides.

2y = 8 - 4

2y = 4

Divide both sides by 2.

y = 4/2

y = 2

So, x = 1, y = 2

~Hope I helped!~
7 0
3 years ago
the cost of plastering a wall of a room having length 8m and heights 4m at 4s 15 per m² is rs 1560 . find the cost of carpeting
Virty [35]

Answer:

Here,

length = 8m

height = 4m

4s = 15 per m^2

Now,

300 per meter = 300 * 15 per m^2

= 4500 per m^2

4 0
3 years ago
Two pools are being drained. To start, the first pool had 3850 liters of water and the second pool had 4370 liters of water. Wat
SashulF [63]

Answer:

(a)

Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes

Amount of water in the second pool (in liters) = 4370 liters - 43 liters per minute * x minutes

(b)

3850 liters - 33 liters per minute * x minutes= 4370 liters - 43 liters per minute * x minutes

Step-by-step explanation:

(a) With x being the minutes after which you want to calculate the amount of water in the pool, to calculate this amount of water you must subtract the water drained from the initial amount of water that the pool contains.

Knowing that, for example, the water from the first pool drains at a rate of 33 liters per minute, then after x minutes, the total water drained will be 33 liters per minute * x minutes. Then:

<u><em>Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes</em></u>

Reasoning in the same way:

<u><em>Amount of water in the second pool (in liters) = 4370 liters - 43 liters per minute * x minutes</em></u>

(b)  Now want to know when the two pools would have the same amount of water.  If they have the same amount of water then you can express:

Amount of water in the first pool = Amount of water in the second pool

Replacing the expressions found in (a):

<u><em>3850 liters - 33 liters per minute * x minutes= 4370 liters - 43 liters per minute * x minutes</em></u>

5 0
3 years ago
 In a survey of 2,200 people who owned a certain type of​ car, 1,210 said they would buy that type of car again. What percent of
katrin [286]

Answer:

55%

If 1,210 people would buy that type of car again, they were satisfied with it.

The fraction of people who were satisfied would be \frac{1210}{2200}.

To find a percentage, we need to divide the top of the fraction by the bottom, then multiply by 100.

1210/2200 is equal to 0.55. This is the decimal form of the fraction, but we need the percentage.

0.55 x 100 is equal to 55.

The answer is 55%

6 0
3 years ago
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