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dmitriy555 [2]
3 years ago
9

The area of a rectangle is 300 square centimeters. If the sides of the rectangle are given as 5 centimeters and

//tex.z-dn.net/?f=%20%5Csqrt%7Bx%2B2600%7D%20" id="TexFormula1" title=" \sqrt{x+2600} " alt=" \sqrt{x+2600} " align="absmiddle" class="latex-formula"> centimeters, then find the value of x and the other side of the rectangle.
Mathematics
1 answer:
joja [24]3 years ago
3 0
<em>x</em> is 1000, and the other side of the rectangle is 60 cm.
Area is found by multiplying length by width.  Using the sides we know we have
300=5(\sqrt{x+2600})
We divide both sides by 5:
\frac{300}{5}=\frac{5\sqrt{x+2600}}{5}&#10;\\&#10;\\60=\sqrt{x+2600}
To "undo" a square root, we square both sides:
60^2=(\sqrt{x+2600})^2&#10;\\&#10;\\3600=x+2600
Subtract 2600 from both sides:
3600-2600=x+2600-2600
1000=x
Now we substitute this into the side with x:
\sqrt{x+2600}=\sqrt{1000+2600}=\sqrt{3600}=60
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To complete this component you will need to insert parentheses in Expression 2 to change the order of operations so the expressi
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Given:

The expression is 5+4\times 2+6-2\times 2-1.

To find:

The position of parentheses inserted in the expression to get the value 19

Step-by-step explanation:

We have,

5+4\times 2+6-2\times 2-1

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What is x2 – 6 = 16x + 30 rewritten in standard form, then factored?
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Answer:

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Step-by-step explanation:

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We have to write  in standard form and then factorize the given equation.

The standard form for a general quadratic equation is given as ax^2+bx+c=0

Consider x^2-6=16x+30

Taking all terms to left side, we have,

x^2-6-16x-30=0

Adding like terms, we have,

x^2-16x-36=0

Now we will factorize it.

We will solve the quadratic equation x^2-16x-36=0 using middle term splitting method,

-16x can be written as -18x+2x

x^2-16x-36=0  becomes

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Taking x common from first two terms  and 2 common from last two terms we have,

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Thus, the factored form of x^2-16x-36=0 is (x+2)(x-18)=0

4 0
3 years ago
Read 2 more answers
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