1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andrej [43]
3 years ago
6

Every seventh-grade student at Martin Middle School takes one world language class.

Mathematics
2 answers:
saw5 [17]3 years ago
6 0
18 students are 1/10 of the number of seventh graders s

18 = 0.1 s

First choice.


Alexus [3.1K]3 years ago
4 0

Answer:

Option (A) 18 = 0.1s

Step-by-step explanation:

Every seventh-grade student at Martin Middle School takes one world language class.

Now we will form the equation as per statement of the question.

Let total students of seventh-grade = s

" one tenth of seventh grade students take  French."

" Students who took French were 18."

So \frac{1}{10} of s = 18

(0.1)s = 18

therefore, Option (A) 18 = 0.1s is the answer.

You might be interested in
How do you simplify fractions in the easiest way
MArishka [77]

Answer:

Divide them by numbers they have in common.

Step-by-step explanation:

8 0
3 years ago
The revenue function for a production by a theatre group is R(t) = -50t^2 + 300t where t is the ticket price in dollars. The cos
Mkey [24]
Break even is the value of t where revenue=cost or R(t)=C(t)

set equal each other

-50t^2+300t=600-50t
multiply both sides by -1
50t^2-300t=50t-600
divide both sides by 50
t^2-6t=t-12
minus t-12 from both sides
t^2-7t+12=0
factor
(t-4)(t-3)=0
set each to zero
t-4=0
t=4

t-3=0
t=3
the cost is $3 or $4

it will first break even at t=3$
7 0
3 years ago
Read 2 more answers
Of one group receive 28 baseball cards and the second group receive 68 baseball card .of each person entering the stadium receiv
antiseptic1488 [7]
Hi, first, the grammar has been a bit confusing, but i think i have it. the question is that one group has 28 baseball cards and another has 68, right? in order to tell how much each person could have received, we first have to know how many people there were and divide the numbers of cards by that. since you never specified the number of people in the groups, i can't solve it completely. all together you have 96 cards. i hope this helps.
6 0
3 years ago
Read 2 more answers
Simplify (6w + 5.2) + (12.2 + 2.3w)
mrs_skeptik [129]

Answer:

The answer is 8.3 W + 17.4

If you click on the image it will show you how to solve the equation and I hope this helps you.

3 0
2 years ago
Noa buys 6 items that each cost $4.25 and 3 items that each cost $6.75. How much does Noa spend in total?
den301095 [7]

Answer:

Answer is D - $45.75

Step-by-step explanation:

(6 x $4.25) + (3 x $6.75) = $45.75

4 0
3 years ago
Read 2 more answers
Other questions:
  • :))) help por favor
    9·1 answer
  • The reading on a voltage meter connected to a test circuit is uniformly distributed over the interval (θ, θ + 1), where θ is the
    13·1 answer
  • A rectangular pyramid is sliced such that the cross section is perpendicular to its base and the cross section does not intersec
    9·2 answers
  • What is the number of possible outcomes in the sample space formed by rolling a dice and flipping 2 coins?
    11·1 answer
  • Is b = 6 a solution to the inequality b – 3 > 5?
    11·1 answer
  • If susan, janice, and melvin take 2.0 hours to walk to their school at a rate of 1.0 m/s, how far is their school from their hou
    15·1 answer
  • a shopkeeper bought 2 watches for rs 400. he sold them to gain 5% one and loss 5% on other. calculate his final gain or loss per
    14·1 answer
  • Statistics question!!!!​
    8·1 answer
  • A little monkey had some peaches. On the first day he decided to keep ½ of his peaches. He gave the rest away. Then he ate one.
    11·1 answer
  • please explain how you got the answer please i need to see how you got that answer!! umm please someone give me it quick
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!