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inysia [295]
3 years ago
9

Given:

Mathematics
2 answers:
Olegator [25]3 years ago
8 0
The answer to this is not possible because sss would be just one angle and they want it to form a congruent triangle
Simora [160]3 years ago
8 0
Given:
∠TRS = ∠URS
∠TSR = ∠USR

Based on the given information and the algebraic and geometric properties presented or proven thus far, choose the congruence theorem that could be used to prove the triangles congruent. If it is not possible to prove the triangles are congruent, choose "not possible".


ASA

∠R≈∠R and ∠S=∠S and RS≈SR
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Compare the integers indicated on the graph below.
Aleks [24]
The correct answer is A. -6 > -12


Hope that helped! :)
3 0
3 years ago
If Sabrina has seven letters, with no repeats, how many possible arrangements are there with the seven letters.
MissTica

Answer:

5040

Step-by-step explanation:

There are 7 possibilities for the first spot, 6 for the second, etc.

7*6*5*4*3*2*1=5040

3 0
2 years ago
6+(-9)= I want a answer<br>​
choli [55]
It would be -3. since they’re different signs you would subtract instead of doing addition. you also would us the greater numbers sign, which, in this case, -9 is the greater number so the answers sign would be negative.
3 0
3 years ago
Read 2 more answers
Find the derivative F(x)=(5x+3)(2x^2+1)
Lerok [7]

Answer:

10x^3 + 6x^2 + 5x + 3

Step-by-step explanation:

F(x)=(5x+3)(2x^2+1)

= 5x*2x^2 + 5x*1 + 3*2x^2 + 3*1

= 10x^3 + 5x + 6x^2 + 3

= 10x^3 + 6x^2 + 5x + 3

3 0
3 years ago
The National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time requir
Paha777 [63]

Answer:

95​% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

Step-by-step explanation:

We are given that the National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time required to earn their bachelor’s degrees. The mean was 5.15 years and the standard deviation was 1.68 years respectively.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                              P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean time = 5.15 years

            \sigma = sample standard deviation = 1.68 years

            n = sample of college graduates = 4400

            \mu = population mean time

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics although we are given sample standard deviation because the sample size is very large so at large sample values t distribution also follows normal.</em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5%

                                               level of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                                              = [ 5.15-1.96 \times {\frac{1.68}{\sqrt{4400} } } , 5.15+1.96 \times {\frac{1.68}{\sqrt{4400} } } ]

                                             = [5.10 , 5.20]

Therefore, 95​% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

8 0
3 years ago
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