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Bogdan [553]
3 years ago
7

Can somebody plz answer my question

Biology
1 answer:
Inessa [10]3 years ago
5 0
The five levels of organization are tissues, cells , organs, organ systems and organisms .
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True or false? The buoyant force on an object depends on the yolume of the object,
oee [108]
True

The greater the object weighs (volume) the heavier it is, and it the object is heavier, the the buoyancy force will be higher

Hope this helps :)
3 0
3 years ago
Students use alphabet letters to represent the genetic instruction for a trait of an organism. The students write these alphabet
Gemiola [76]

Answer: b

Explanation: asexual have identical offspring sexual will have different/unique offspring which means they won’t be the exact same.

5 0
3 years ago
Read 2 more answers
6. Which is not a product of photosynthesis? nitrogen glucose water oxygen
Artyom0805 [142]
Nitrogen is not a product of photosynthesis
4 0
2 years ago
If a snake species were introduced to an ecosystem where it had no natural predators,
Butoxors [25]

Answer:

I would say the answer is the first one, "They would compete with native snake species for resources, causing a decline in native snakes"    I'm not 100% sure i'm right but i'm pretty sure I am right ...

Explanation:

5 0
3 years ago
Read 2 more answers
Alkaptoneuria is a recessive genetic disorder found among North American populations at a frequency of about 1 in 500,000 births
Dafna11 [192]

Answer:

The correct answer is - 1/41,493

Explanation:

Let assume the frequency of the two possible same allele genotype (dominant and recessive) in an inbred population is p and q. Then the frequency of heterozygotes (H) is denoted as:

2pq + 2pqF.  ( where F is the inbreeding coefficient).

The frequency of the two different hoozygotes in inbred population can be calculated as:

p2 + pqF and q2 + pqF. (Where p and q are the allele frequency of the dominant and recessive phenotype.

Given: Frequency of Alkaptonuria (q 2) = 1:500, 000

=> q = 1/707

p = 706/707 ( Approx values)

solution:

Inbreeding coefficient (F) = 1/64

Therefore,

Frequency of Alkaptonuria in second cousins= q 2 + pqF

= 1/500, 000 + (706/707 x 1/707) x (1/64)

= 1/500, 000 + 1/45, 248

= 1/41,493 (approx)

5 0
3 years ago
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