Answer:
y = 12^8
Step-by-step explanation:
Log base 12, y^2 = 16
y2 = 12^16
y = sqrt ( 12^16) = (12^16)^1/2
y = 12^8
For this case, what you should do is use any computational tool and graph the data in the table. For example, I used excel.
In the x axis we have Starting temperature and in the axis of the y we have Ending temperature.
You can see how the diagram varies almost linearly.