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HACTEHA [7]
3 years ago
14

Clyde simplified ( j^-8)^-2

Mathematics
2 answers:
quester [9]3 years ago
8 0

Answer:

Clyde should have applied the power of a power rule and multiplied the exponents instead of adding them. The simplified form should be j to the 16th power.

Step-by-step explanation:

The exponents should be multiplied.

The simplified form should be j^16

Lina20 [59]3 years ago
5 0

ANSWER

{j}^{16}

EXPLANATION

The given expression is

( {j}^{ - 8} )^{ - 2}

To simplify this expression, we use the law of exponents.

Recall that:

{(a}^{m} )^{n}  =  {a}^{mn}

We need to multiply the exponents to get:

( {j}^{ - 8} )^{ - 2}  = {j}^{ - 8 \times - 2}

( {j}^{ - 8} )^{ - 2}  = {j}^{16}

Therefore after simplification, Clyde got:

{j}^{16}

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Solve for u . <br><br> - 4u + 38 = 2(u-8)<br><br> Simplify your answer as much as possible.
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Hi there!
Let's solve this equation step by step!

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Ymorist [56]

Answer:

First Question

lower limit of 9 mph  j =  8.5 \  mph

upper  limit of 9 mph q =  9.5 \  mph

Second Question

lower limit of 120 pounds is  i =  119.9 \  pounds

upper limit of 120 pounds is  l =  120.1 \  pounds

Third  Question

lower limit of 187 pounds is  a =  186.75 \  pounds

upper limit of 187 pounds is  b =  187.25 \  pounds  

Step-by-step explanation:

From the question we are told that

  The amount of beer administered is  three 12-ounce beers

  The  amount of coffee administered is  two cups of coffee

  The  speed limit is   60-mph

  The smallest unit of scale is  1 mph

  The first subject scores 9 mph

Generally given that the smallest unit of scale is  1 mph then the deviation of  9 mph will be by \frac{1}{2} \ mph

Hence the lower limit of 9 mph is

    j =  9 - 0.5

    j =  8.5 \  mph

And  the upper  limit of 9 mph is

    q =  9 + 0.5

    q =  9.5 \  mph    

Generally given that the measuring weight on a scale that is accurate to the nearest 0.2 pound then 120 pounds will deviate by  \frac{1}{0.2} \ pounds

Hence the lower limit of 120 pounds is

    i =  120 - 0.1

    i =  119.9 \  pounds

And  the upper  limit of 120 pounds is

    l =  120 + 0.1

    l =  120.1 \  pounds    

Generally given that the measuring weight on a scale that is accurate to the nearest 0.5 pound then  187 pounds will deviate by  \frac{1}{0.5} \ pounds = 0.25 \ pounds

Hence the lower limit of 120 pounds is

    a =  187 - 0.25

    a =  186.75 \  pounds

And  the upper  limit of 120 pounds is

    b =  187 + 0.25

    b =  187.25 \  pounds      

5 0
4 years ago
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