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HACTEHA [7]
3 years ago
14

Clyde simplified ( j^-8)^-2

Mathematics
2 answers:
quester [9]3 years ago
8 0

Answer:

Clyde should have applied the power of a power rule and multiplied the exponents instead of adding them. The simplified form should be j to the 16th power.

Step-by-step explanation:

The exponents should be multiplied.

The simplified form should be j^16

Lina20 [59]3 years ago
5 0

ANSWER

{j}^{16}

EXPLANATION

The given expression is

( {j}^{ - 8} )^{ - 2}

To simplify this expression, we use the law of exponents.

Recall that:

{(a}^{m} )^{n}  =  {a}^{mn}

We need to multiply the exponents to get:

( {j}^{ - 8} )^{ - 2}  = {j}^{ - 8 \times - 2}

( {j}^{ - 8} )^{ - 2}  = {j}^{16}

Therefore after simplification, Clyde got:

{j}^{16}

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