The rule we'll use is
p^(q*r) = (p^q)^r
The exponents have been rearranged a bit.
In this case, p = 3.14, q = 159 and r = x, so,
p^(q*r) = (p^q)^r
3.14^(159*x) = (3.14^159)^x
This is in the form A^x with A = 3.14^159
Answer:
Drugs
Step-by-step explanation:
No literally drugs can make you pass out.
Answer:
Step-by-step explanation:
label sides adjacent h and o
sin(30) times 12 = 6 = 10
Notice, ending ends makes it easeier
1+20=21
2+19=21
...
10+11=21
there are 10 pairs of numbers
they add to 21
10 times 21=210
the sum is 210
