Answer:
The minimum value of the bill that is greater than 95% of the bills is $37.87.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

What are the minimum value of the bill that is greater than 95% of the bills?
This is the 95th percentile, which is X when Z has a pvalue of 0.95. So X when Z = 1.645.




The minimum value of the bill that is greater than 95% of the bills is $37.87.
38.2 is the quotient!!!!
Hope this helps
The answer to 188x31 is 5,828
Answer:
d. 14
Step-by-step explanation:
- 3(2) = 3 × 2 = 6
- Plug 6 in: 12 + {10 ÷ [11 - 6]}
- 11 - 6 = 5
- Plug 5 in: 12 + {10 ÷ 5}
- 10 ÷ 5 = 2
- Plug 2 in: 12 + 2
- 12 + 2 = 14
I hope this helps!