In the event that a line has no y-intercept, that implies it never converges the y-intercept, so it must be parallel to the y-intercept. This implies it is a vertical line, for example, . This slant of this line is vague. In the event that the line has no x-intercept, at that point it never meets the x-intercept, so it must be parallel to the x-pivot.
If x-intercept is -2 the line would be vertical as the y-intercept = 0.
Answer:
The probability that the town has 30 or fewer residents with the illness = 0.00052.
Step-by-step explanation:
So, we have the following set of data or information or parameters given from the question above and they are; the number of people living in that particular society/community/town = 74,000 residents and the proportion of people that the diseases affected = .000215.
The first step to do is to determine the expected number of people with disease. Thus, the expected number of people with disease = 74,000 × .000215 = 15.91.
Hence, the probability that the town has 30 or fewer residents with the illness = 1.23 × 10^-7 × 15.91^30/ 2.65253 × 10^-32 = 0.00052.
Note the formula used in the calculating the probability that the town has 30 or fewer residents with the illness = e^-λ × λ^x/ x!
So there is this chart my teacher showed me to help find the answers to your questions I will send a picture but here are the answers
30km is 18.642m
44,000in is 111760cm
21ft is 6.401m
0.75m I’m not for sure sorry but
133yards is 121615.2mm
I hope that helps sorry I did not understand the one question 0.75m
The law of cosines for this particular situation is b^2 = a^2 + c^2 - 2ac cosB.
Filling in what you know, you have b^2 = 25 + 49 - [2(5)(7)-.1908], which simplifies to b^2 = 74 - 69.8092 which gives you a b^2 value of 4.1908, but you have to take the square root of that so you get a side value for b of 2.05.
Surface area is just the area of all these 4 triangles plus the rectangle.
First we can find the area of the rectangle.
Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.
The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:
Calculate the area:
We have two of these triangles.
Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:
Now find the area:
We have two of these triangles.
Add all the areas together:
