Answer:
<em>371 women had their pregnancy between 250 days and 282 days in length.</em>
di po ako sure sa answer ko, but it is based on what I remembered.
Step-by-step explanation:
z=<u>532-266</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u>1</u><u>6</u><u> </u><u> </u>
√500
= 371.74 or 371
hard to see the answers on the screen with the glare but the answer is 2.4 so I would say if there is a choice between 2 and 3 that would be the answer
Answer:
C. a = 7
D. c = -3
Step-by-step explanation:
C. 7(2a + 3) + 21 = 100+ 40
14a + 21 + 21 = 140
14a = 140 - 21 - 21
14a = 98
a = 7
D. 6+ 14 - 12c = 56
20 - 12c = 56
-12c = 56 - 20
-12c = 36
c = - 3
Answer:
Yes, we can assume that the percent of female athletes graduating from the University of Colorado is less than 67%.
Step-by-step explanation:
We need to find p-value first:
z statistic = (p⁻ - p0) / √[p0 x (1 - p0) / n]
p⁻ = X / n = 21 / 38 = 0.5526316
the alternate hypothesis states that p-value must be under the normal curve, i.e. the percent of female athletes graduating remains at 67%
H1: p < 0.67
z = (0.5526316 - 0.67) / √[0.67 x (1 - 0.67) / 38] = -0.1173684 / 0.076278575
z = -1.538681
using a p-value calculator for z = -1.538681, confidence level of 5%
p-value = .062024, not significant
Since p-value is not significant, we must reject the alternate hypothesis and retain the null hypothesis.
Answer:
3
Step-by-step explanation:
3x(6+3)=27, shed have 1 inch left over