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Goryan [66]
3 years ago
6

If f(x) = 4x^2and g(x) = x+1, find (f•g)(x).

Mathematics
2 answers:
Furkat [3]3 years ago
6 0

Answer:

(f*g)(x) = 4x^2(x+1)\\(f*g)(x) = 4x^3+4x^2

Step-by-step explanation:

f(x) = 4x^2\\g(x) = x+1

So,

Multiplying both equations

(f*g)(x) = 4x^2(x+1)\\(f*g)(x) = 4x^3+4x^2

vazorg [7]3 years ago
4 0

Answer:

(f.g)(x)=4x^3+4x^2

Step-by-step explanation:

f(x) = 4x^2and g(x) = x+1, (f•g)(x)=?

(f.g)(x)=f(x)*g(x)

(f.g)(x)=4x^2*(x+1)

(f.g)(x)=4x^3+4x^2

hope it helps. .brainliest please

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The formula F=95C+32 changes a temperature reading from the Celsius scale C to the Fahrenheit scale F. What is the temperature m
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Answer:

122°F

Step-by-step explanation:

F=(50×9/5)+32

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8 0
2 years ago
The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in
Stolb23 [73]

Answer:

ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75

±0.75 ounce

Step-by-step explanation:

Assuming this complete question: The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in that state. To do this, they have selected a random sample of 300 people from the designated population. The following results were recorded: xbar=34.5 ounces, s=7.9 ounces Given this information, if the leaders wish to estimate the mean milk consumption with 90 percent confidence, what is the approximate margin of error in the estimate?

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=34.5 represent the sample mean

\mu population mean (variable of interest)

s=7.9 represent the sample standard deviation

n=300 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=300-1=299

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,199)".And we see that t_{\alpha/2}=1.653

And the margin of error is given by:

ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75

±0.75 ounce

4 0
3 years ago
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so total measure of all angles in octagon = 8 * 135 =  1080 degrees
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3 years ago
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