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Goryan [66]
3 years ago
6

If f(x) = 4x^2and g(x) = x+1, find (f•g)(x).

Mathematics
2 answers:
Furkat [3]3 years ago
6 0

Answer:

(f*g)(x) = 4x^2(x+1)\\(f*g)(x) = 4x^3+4x^2

Step-by-step explanation:

f(x) = 4x^2\\g(x) = x+1

So,

Multiplying both equations

(f*g)(x) = 4x^2(x+1)\\(f*g)(x) = 4x^3+4x^2

vazorg [7]3 years ago
4 0

Answer:

(f.g)(x)=4x^3+4x^2

Step-by-step explanation:

f(x) = 4x^2and g(x) = x+1, (f•g)(x)=?

(f.g)(x)=f(x)*g(x)

(f.g)(x)=4x^2*(x+1)

(f.g)(x)=4x^3+4x^2

hope it helps. .brainliest please

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Which ordered pair represents the y-intercept of the graph of the equation y = -3x - 9?
Mnenie [13.5K]
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Equation
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y = -3x - 9

------------------------------------------------------------------------------------------
Option 1
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If I substitute x = -9, I should get y = 0

When x = -9
y = -3 (-9) - 9
= 18 (I did not get 0, wrong)


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Option 2
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If I substitute x = -3, I should get y = 0
y = -3(-3) - 9
y = 9 - 9 
y = 0 (Yes, I got 0, correct)


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Option 3
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If I substitute x = 0, I should get y = -3
y = -3 (0) - 9
y = 0 - 9
y = -9 (I did not get -3, wrong)


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Option 4
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If I substitute x = 0, I should get y = -9
y = -3 (0) - 9
y = 0 - 9
y = -9 (Yes, I got -9, correct)


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Answer: (-3, 0) and (0, 9) are ordered pairs of the equation (Answer B, D)
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7 0
3 years ago
The first derivative of x^2+2y^2=16 is -x/(2y), the second is -(2y^2+x^2)/(4y^3). Find the third implicit derivative of x^2+2y^2
gtnhenbr [62]

Answer:

d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)

Step-by-step explanation:

d²y/dx² = (-2y² − x²) / (4y³)

Take the derivative (use quotient rule and chain rule):

d³y/dx³ = [ (4y³) (-4y dy/dx − 2x) − (-2y² − x²) (12y² dy/dx) ] / (4y³)²

d³y/dx³ = [ (-16y⁴ dy/dx − 8xy³ − (-24y⁴ dy/dx − 12x²y² dy/dx) ] / (16y⁶)

d³y/dx³ = (-16y⁴ dy/dx − 8xy³ + 24y⁴ dy/dx + 12x²y² dy/dx) / (16y⁶)

d³y/dx³ = ((8y⁴ + 12x²y²) dy/dx − 8xy³) / (16y⁶)

d³y/dx³ = ((2y² + 3x²) dy/dx − 2xy) / (4y⁴)

Substitute:

d³y/dx³ = ((2y² + 3x²) (-x / (2y)) − 2xy) / (4y⁴)

d³y/dx³ = ((2y² + 3x²) (-x) − 4xy²) / (8y⁵)

d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)

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3 years ago
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a square garden has an area of 225 square feet. how much fencing will a gardener need to buy in order to place fencing around th
IgorC [24]
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3 years ago
Find the constant $a$ such that\[(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28.\]
Colt1911 [192]

The value of constant a is -5

Further explanation:

We will use the comparison of co-efficient method for finding the value of a

So,

Given

(x^2 - 3x + 4)(2x^2 +ax + 7)\\= x^2((2x^2 +ax + 7)-3x((2x^2 +ax + 7)+4(2x^2 +ax + 7)\\= 2x^4+ax^3+7x^2-6x^3-3ax^2-21x+8x^2+4ax+28\\Combining\ alike\ terms\\=2x^4+ax^3-6x^3+7x^2-3ax^2+8x^2-21x+4ax+28\\= 2x^4 +(a-6)x^3+(15-3a)x^2-(21-4a)x+28\\

As it is given that

(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28

In this case, co-efficient of variables will be equal, so we can compare the coefficients of x^3, x^2 or x

Comparing coefficient of x^3

a-6 = -11\\a = -11+6\\a = -5

So the value of constant a is -5

Keywords: Polynomials, factorization

Learn more about factorization at:

  • brainly.com/question/1414350
  • brainly.com/question/1430645

#LearnwithBrainly

4 0
3 years ago
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3x^-2 y^0  simplify

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