I hope this helps you
f (x)=(x+2)^3/2
f'(x)=3/2. (x+2)^3/2-1
f'(x)=3/2 (x+2)^1/2
f'(x)=3/2.square root of (x+2)
Equation : c = (2.80 / 7) + 0.75
Normal price of each cookie:
c = (2.80 / 7) + 0.75
c = 0.4 + 0.75
c = $1.15
Answer:
The degrees of freedom are given by;
![df =n-1= 5-1=4](https://tex.z-dn.net/?f=%20df%20%3Dn-1%3D%205-1%3D4)
The significance level is 0.1 so then the critical value would be given by:
![F_{cric}= 7.779](https://tex.z-dn.net/?f=%20F_%7Bcric%7D%3D%207.779)
If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays
Step-by-step explanation:
For this case we have the following observed values:
Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100
For this case the expected values for each day are assumed:
![E_i = \frac{100}{5}= 20](https://tex.z-dn.net/?f=%20E_i%20%3D%20%5Cfrac%7B100%7D%7B5%7D%3D%2020)
The statsitic would be given by:
![\chi^2 = \sum_{i=1}^n \frac{(O_i-E_i)^2}{E_i}](https://tex.z-dn.net/?f=%20%5Cchi%5E2%20%3D%20%5Csum_%7Bi%3D1%7D%5En%20%5Cfrac%7B%28O_i-E_i%29%5E2%7D%7BE_i%7D)
Where O represent the observed values and E the expected values
The degrees of freedom are given by;
![df =n-1= 5-1=4](https://tex.z-dn.net/?f=%20df%20%3Dn-1%3D%205-1%3D4)
The significance level is 0.1 so then the critical value would be given by:
![F_{cric}= 7.779](https://tex.z-dn.net/?f=%20F_%7Bcric%7D%3D%207.779)
If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays
Answer: Milimeters (mm)
Step-by-step explanation: