Answer:
kflhddddddddddddnbhpppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp
Step-by-step explanation:
<h3>I'll teach you how to solve 4m^2 - 10= -6</h3>
-----------------------------------------------------
Add 10 to both sides:
4m^2-10+10= -6+10
Simplify:
4m^2= 4
Divide both sides by 4:
4m^2/4= 4/4
Simplify:
m^2= 1
For x^2 = f(a) the solutions are x =
-
:
m=
, m= -
Simplify:
m = 1, m = -1
Your Answer Is m = 1, m = -1
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Answer:
The relation represents a growth when b>1 and a decay when 0<b<1
Step-by-step explanation:
Any function in the form
, where a > 0, b > 0 and b not equal to 1 is called an exponential function with base b. If 0 < b < 1. It is an example of an exponential decay. The general shape of an exponential with b > 1 is an example of exponential growth. An exponential function is expressed in the form
The relation represents a growth when b >1 and a decay when 0<b<1.
Answer:
9.34%
Step-by-step explanation:
p = 4%, or 0.04
n = Sample size = 667
u = Expected value = n * p = 667 * 0.04 = 26.68
SD = Standard deviation =
= 5.06
Now, the question is if the manager is correct, what is the probability that the proportion of flops in a sample of 667 released films would be greater than 5%?
This statement implies that the p-vlaue of Z when X = 5% * 667 = 33.35
Since,
Z = (X - u) / SD
We have;
Z = (33.35 - 26.68) / 5.06
Z = 1.32
From the Z-table, the p-value of 1.32 is 0.9066
1 - 0.9066 = 0.0934, or 9.34%
Therefore, the probability that the proportion of flops in a sample of 667 released films would be greater than 5% is 9.34%.
Answer:
5 1/6
Step-by-step explanation:
Rewriting our equation with parts separated
=8+2/4−3−1/3
Solving the whole number parts
8−3=5
Solving the fraction parts
2/4−1/3=?
Find the LCD of 2/4 and 1/3 and rewrite to solve with the equivalent fractions.
LCD = 12
6/12−4/12=2/12
Reducing the fraction part, 2/12,
2/12=1/6
Combining the whole and fraction parts
5+1/6=5 1/6