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PolarNik [594]
2 years ago
10

Ou have traveled 25 miles in 2 minutes and come to a standstill. What was your initial velocity?

Mathematics
1 answer:
Illusion [34]2 years ago
4 0
If you traveled 25 miles in 2 minutes, your average speed was 25 miles per 2 minutes or 750 miles per hour. If your rate of deceleration was constant, your initial speed was two times 750 miles per hour or 1500 mph. 

<span>I do not have enough information to determine your initial velocity because I don't know what direction you were going, and velocity is speed with direction.</span>
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Can someone help plz?????
Keith_Richards [23]

Answer:

B

Step-by-step explanation:

-2-(-4) = -2 + 4

B shows subtracting 2 to the left then adding 4 to the right.

6 0
3 years ago
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(50 POINTS AND BRAINLIEST) Show all work to multiply quantity 2 plus the square root of negative 25 end quantity times quantity
xeze [42]
The equation would be (3+√-16)(6-√-64)
A negative square root can not be a real number, meaning that we have to use the imaginary number.
(3+4i)(6-8i)
How to multiply imaginary numbers...
Treat this like an equation looking like (x-a)(y-b)
Use FOIL
(3+4i)(6-8i)
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8 0
3 years ago
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394.6 divided by 9 using compatible numbers to estimate the quotient?
Maru [420]
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5 0
3 years ago
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What is the vertex (x,y)? h(t)=2x^2+4x+7<br> PLS SHOW WORK
Nesterboy [21]
Hack
for y=ax^2+bx+c
the xvalue of the vertex is -b/2a
and the y value is found by subsituting that for x

so

-b/2a

h(t)=2x^2+4x+7
a=2
b=4
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6 0
3 years ago
An 8.0 kg block is moving at 3.2 m/s. A net force of 10 N is constantly applied on the block in the direction of its movement, u
Softa [21]

Answer:

5.02 m/s

Step-by-step explanation:

We are given that

Mass of block,m=8 kg

Initial velocity,u=3.2 m/s

Net force ,F=10 N

Distance,s=6 m

We have to find the approximate final velocity of the block.

We know that a=\frac{F}{m}

Using the formula

a=\frac{10}{8}=\frac{5}{4} m/s^2

We know that

v=\sqrt{u^2+2as}

Using the formula

v=\sqrt{(3.2)^2+2\times \frac{5}{4}\times 6}

v=5.02 m/s

8 0
2 years ago
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