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Elis [28]
3 years ago
15

I need the answer for this 2120 = 18x + 320

Mathematics
2 answers:
steposvetlana [31]3 years ago
5 0

Answer:

x = 100

Step-by-step explanation:

2120 - 320 = 1800

1800 ÷ 18 = 100

grigory [225]3 years ago
3 0

Answer:

100

Step-by-step explanation:

we need to swap sides so we take the 320 and put it in the other side but in negative form and that comes out to 1800 and then we divide that by 18

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Sara’s boss informed her she is getting a 5% raise. She currently makes $22 per hour. What is her new hourly wage?
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22(0.05) = 1.1
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5 0
3 years ago
Read 2 more answers
2.Assume that x is a binomial random variable with n=1000 and p=0.50. Use a normal approximation to find each of the following p
natima [27]

Answer:

a) 0.4761

b) 0.2118

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 1000, p = 0.5

So

\mu = E(X) = np = 1000*0.5 = 5000

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{1000*0.5*0.5} = 15.81

a)P(x>500)

This is 1 subtracted by the pvalue of Z when X = 501. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{501 - 500}{15.81}

Z = 0.06

Z = 0.06 has a pvalue of 0.5239

1 - 0.5239 = 0.4761

b)P(490≤x<500)

This is the pvalue of Z when X = 499 subtracted by the pvalue of Z when X = 490. So

X = 499

Z = \frac{X - \mu}{\sigma}

Z = \frac{499 - 500}{15.81}

Z = -0.06

Z = -0.06 has a pvalue of 0.4761

X = 490

Z = \frac{X - \mu}{\sigma}

Z = \frac{490 - 500}{15.81}

Z = -0.63

Z = -0.63 has a pvalue of 0.2643

0.4761 - 0.2643 = 0.2118

6 0
3 years ago
Fred and Ben each ran laps around the track. Fred completed his run in 16 minutes. Ben completed his run in 3/4 of the amount of
m_a_m_a [10]

Answer:

Time required by Ben was 12 minutes.

Step-by-step explanation:

Given:

Time Required for Fred = 16 mins

Ben completed his run in 3/4 of the amount of time of Freds run.

We need to find the time required by Ben.

Now Given that;

Ben completed his run in 3/4 of the amount of time of Freds run.

It means that time required by Ben is equal to 3/4  times time required by Fred.

Time required by Ben = \frac{3}{4}\times  Freds \ run

Time required by Ben = \frac{3}{4}\times 16 = 12\ mins

Hence Time required by Ben was 12 minutes.

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Step-by-step explanation:

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