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NISA [10]
4 years ago
9

Find the value of y for which the value of 1.7y+37 is 14 less than the value of 9.3y–25 HELP QUICK

Mathematics
1 answer:
Harrizon [31]4 years ago
4 0

Answer:

y=10

Step-by-step explanation:

1.7y+37 is 14 less than the value of 9.3y–25

  • 1.7y + 37 = 9.3y - 25 - 14
  • 1.7y + 37 = 9.3y - 39
  • 9.3y - 1.7y = 37 + 39
  • 7.6y = 76
  • y = 76/7.6
  • y = 10

Answer is 10

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Step-by-step explanation:

Given : You and a friend play a game where you each toss a balanced coin.

sample space for tossing two coins : {TT, HT, TH, HH}

Let Y denotes the  winnings on a single play of the game.

You win $1; if the faces are both heads

then P(Y=1)=P(TT)=\dfrac{1}{4}=0.25

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then P(Y=6)=P(HH)=\dfrac{1}{4}=0.25

You loose $3; if the faces do not match.

then P(Y=1)=P(TH, HT)=\dfrac{2}{4}=0.50

The expected value to win : E(Y)=\sum_{i=1}^{i=3} y_ip(y_1)

=1\times0.25+6\times0.25+(-3)\times0.50=0.25

Hence, the mean of Y : E(Y)= $0.25

E(Y^2)=\sum_{i=1}^{i=3} y_i^2p(y_i)\\\\=1^2\times0.25+6^1\times0.25+(-3)^2\times0.5\\\\=0.25+1.5+4.5=6.25

Variance = E[Y^2]-E(Y)^2

=6.25-(0.25)^2=6.25-0.0625=6.1875\approx6.19

Hence, variance of Y = $ 6.19

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Step-by-step explanation:

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Bezzdna [24]

Answer:

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Step-by-step explanation:

4(5y−8−2)=185−15

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