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2 years ago

What is the standard form? 8x^2 + 2x^3

Mathematics

1 answer:

daser333 [38]2 years ago

6 0

Answer:

..........

Step-by-step explanation:

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17. Find x. Round to the nearest tenth if necessary. Assume that segments that appear to be

AlexFokin [52]

Answer:

x=19

Step-by-step explanation:

9*(9+15)=8*(8+x)

9*(24)=8(x+8)

216=8x+64

216-64=8x+64-64

152=8x

152/8=8x/8

19=x

x=19

8 0

2 years ago

Draw the image of the rotation of quadrilateral SORT by 270° about the origin

cestrela7 [59]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

PLEASE HELP I DONT KNOw all THE DEFINITIONS TO THESE- MARK BRAINLIEST TOO

frozen [14]

Answer:

Factor

−

out of

−

(

−

)

Step-by-step explanation:

4 0

3 years ago

I need help please right answers only

yarga [219]

Answer:

-3/2

Step-by-step explanation:

Count up three times and to the left twice. Let me know if you need help with other questions!

7 0

2 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

astra-53 [7]

Answer:

$3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}$

Step-by-step explanation:

The period of the functions $y=a\cos(bx+c)$ , $y=a\sin(bx+c)$ , $y=a\sec (bx+c)$ or $y=a\csc(bx+c)$ can be calculated as

$T=\dfrac{2\pi}{b}$

The period of the functions $y=a\tan(bx+c)$ or $y=a\cot(bx+c)$ can be calculated as

$T=\dfrac{\pi}{b}$

A. The period of the function $y=-3\tan 3x$ is

$T=\dfrac{\pi}{3}$

B. The period of the function $y=6\sin 3x$ is

$T=\dfrac{2\pi}{3}$

C. The period of the function $y=-4\cot \dfrac{x}{4}$ is

$T=\dfrac{\pi}{\frac{1}{4}}=4\pi$

D. The period of the function $y=2\cos \dfrac{2x}{3}$ is

$T=\dfrac{2\pi}{\frac{2}{3}}=3\pi$

E. The period of the function $y=-\dfrac{2}{3}\sec \dfrac{x}{5}$ is

$T=\dfrac{2\pi}{\frac{1}{5}}=10\pi$

5 0

3 years ago