X-2(-4)=2
X+8=2
-8. -8
X=-6. (-6,-4)
4-2y=2
-4. -4
-2y=-2
Divide both sides by-2
Y=1. (4,1)
(3 x 1 ) + (4 x 0.1) + (9 x 0.01) + ( 9 x 0.001)
OR
3 + 0.4 + 0.09 + 0.009
Three and four hundred ninety-nine thousandths
Hope this helped!
Answer:
Step-by-step explanation:
hello :
5x²+8x-4 quadratic expression when : a = 5 and b=8 and c= -4
∆ = b²-4ac ∆ = 8²-4(5)(-4) = 64 +80 = 144 = 12²
X1 = ( -b -√∆)/2a X1 = (-8-12)/10 = -20/10= -2
X2 =(-b+√∆)/2a X2 = (-8+12)/10 = 4/10 = 2/5
us factorisation : a(X-X1)(X-X2)
5x²+8x-4= 5(x+2)(x-2/5) = (x+2)(5x-2)
you can verify ; (x+2)(5x-2) = 5x²-2x+10x-4 = 5x²+8x-4
.4 and .40 are indeed the same amount.
We usually drop the 0 in the 100'ths place when it is not necessary for indicating money or solving a problem with 2 decimals.
Also realize that .400 .4000 etc are all the same as well.
Goal: solve for y. First step: Multiply out 5(y+2) and also 4(2y-1):
5y + 10 and 8y - 4
Then your original <span>5(y+2) = 13+ 4(2y-1)
becomes 5y + 10 = 13 + 8y - 4
Combining the y terms: </span>10 = 13 + 3y - 4
Simplifying the right side: 10 = 3y + 9
Subtracting 9 from both sides: 1 = 3y. Solving for y: y = 1/3