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3 years ago

X+15=6 What does x equal?

Mathematics

2 answers:

Paraphin [41]3 years ago

8 0

Answer:

-9

Step-by-step explanation:

When you add some thing to a negative that means you are actually subtract that number

Vedmedyk [2.9K]3 years ago

4 0

Answer:

x=-9

Step-by-step explanation:

6-15=-9

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Write the equation in standard form of the line that has x-intercept 6 and y-intercept -2.

zysi [14]

Answer:

x - 3y = 6

Step-by-step explanation:

Equation of the line in intercept form

The intercept form of the equation of a line is:

$\displaystyle \frac{x}{a}+\frac{y}{b}=1$

Where:

a = x-intercept

b = y-intercept

The standard form of a line is:

Ax + By = C

The given line has a=6 and b=-2, thus:

$\displaystyle \frac{x}{6}+\frac{y}{-2}=1$

Multiplying by 6:

x - 3y = 6

This is the required standard form of the line.

Thus, the standard form of the line is:

x - 3y = 6

8 0

3 years ago

What is 4.2 = c/8 And it would be a lot helpful

liberstina [14]

Step-by-step explanation:

c = 8 × 4.2 (move 8 from the denominator to the side where the 4.2 is - make c the subject)

c = 33.6

7 0

3 years ago

Read 2 more answers

Write down the integer values satisfied by this diagram.

Alinara [238K]

Step-by-step explanation:

well it represents

-1 < X ≥ 3

so answer is 0 1 2 3

7 0

3 years ago

Can someone put an answer for each box plzzzz.

Dahasolnce [82]

We need the drop down options..

7 0

3 years ago

Help me with question a please ! With full workings !

frosja888 [35]

A)

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
P&({{ 0.5}}\quad ,&{{ 0}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$

$\bf QP=\sqrt{(0.5-0)^2+(0-2)^2}\implies QP=\sqrt{0.5^2+2^2}
\\\\\\
QP=\sqrt{\left( \frac{1}{2} \right)^2+4}\implies QP=\sqrt{ \frac{1^2}{2^2}+4}\implies QP=\sqrt{\frac{1}{4}+4}
\\\\\\
QP=\sqrt{\frac{17}{4}}\implies QP=\cfrac{\sqrt{17}}{\sqrt{4}}\implies QP=\cfrac{\sqrt{17}}{2}$

b)

since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP

thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)

c)

what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
R&({{ -0.5}}\quad ,&{{ 0}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-0.5-0}\implies \cfrac{-2}{-0.5}$

$\bf m=\cfrac{\frac{-2}{1}}{-\frac{1}{2}}\implies \cfrac{-2}{1}\cdot \cfrac{2}{-1}\implies 4
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=4(x-0)\implies y=4x+2\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}$

7 0

3 years ago