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lyudmila [28]
4 years ago
12

A disadvantage of the contention approach for LANs, such as CSMA/CD, is the capacity wasted due to multiple stations attempting

to access the channel at the same time. Suppose that time is divided into discrete slots, with each of N stations attempting to transmit with probability p during each slot. What fraction of slots are wasted due to multiple simultaneous transmission attempts
Mathematics
1 answer:
sammy [17]4 years ago
8 0

Answer:

The overview of the given problem is outlined in the following segment on the explanation.

Step-by-step explanation:

The proportion of slots or positions that have been missed due to numerous concurrent transmission incidents can be estimated as follows:

Checking a probability of transmitting becomes "p".

After considering two or even more attempts, we get

Slot fraction wasted,

= [1-no \ attempt \ probability-first \ attempt \ probability-second \ attempt \ probability+...]

On putting the values, we get

= 1-no \ attempt \ probability-[N\times P\times probability \ of \ attempts]

= 1-(1-P)^{N}-N[P(1-P)^{N}]

So that the above seems to be the right answer.

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What is the value of the expression below when w = 3. 4w^2 - 7w - 8
Makovka662 [10]
<h2>Answer:<em> </em><em><u>w =(-40-√4320)/-34=(20+6√ 30 )/17= 3.110 </u></em></h2><h2><em><u> w =(-40+√4320)/-34=(20-6√ 30 )/17= -0.757</u></em></h2>

Step-by-step explanation:  The prime factorization of  4320   is

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To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

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