2 years ago

2 oranges and 3 lemons cost 64p 3 oranges and 4 lemons cot 89p whats the cost of an orange?

Mathematics

1 answer:

adelina 88 [10]2 years ago

3 0

Answer:

The cost of an orange is 21.5

Step-by-step explanation:

let orange be O and lemon be L

it becomes simultaneous Equations

2O+3L=64----1. x3

3O+4L=89----2. x2

6O+12L=192

6O+8L=178

subtracting

4L=14

L=7

put 7 for L in equ 1

2O+3(7)=64

2O+21=64

2O=64-21

2O=43

O=21.5

You might be interested in

Free to whoever gets it

liraira [26]

LolAnswer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Write the equation of the line that passes through the points (-6,-1) and (-4,2). Put your answer in fully simplified point-slop

Archy [21]

$(\stackrel{x_1}{-6}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{-4}-\underset{x_1}{(-6)}}} \implies \cfrac{2 +1}{-4 +6} \implies \cfrac{ 3 }{ 2 }$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{\cfrac{3}{2}}(x-\stackrel{x_1}{(-6)}) \implies {\large \begin{array}{llll} y +1= \cfrac{3}{2} (x +6) \end{array}}$