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Maksim231197 [3]
3 years ago
14

A pyramid has a square base with 8 sides and a slant height of 5

Mathematics
1 answer:
Fofino [41]3 years ago
3 0
If you want the area, it would be around 166.45


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Algebra 1 (pic included)
Marizza181 [45]
If you are given that b = 2, then just plug it in:
2(2)-4 = 4-4 = 0

So, your final answer is 0.
3 0
3 years ago
Find the prime factorization of each number
In-s [12.5K]
   58               212                     2800                900
  /    \              /    \                  /            \              /  \
29    2          2    106           700          4           3  300 
                          /    \          /      \        /  \              /    \  
                        2     53     70     10    2   2          3     100  
                                        /  \     /   \                            /   \ 
                                      7 10   5   2                         2    50
                                         /  \                                         /  \
                                       5    2                                     5  10
                                                                                        /   \ 
                                                                                      5    2
The prime factors are in bold. 
3 0
3 years ago
Sum term product factor quotients coefficients for 5x+12
Svetllana [295]
I tried I hope this helps in any kind of way

4 0
3 years ago
The area of a circular field is 16π square miles. What is the diameter of the field in miles.
ella [17]

Answer:

8

Step-by-step explanation:

1. Divide the area (in square units) by Pi (approximately 3.14159).

2. Take the square root of the result. This is the radius.

3. Now double the radius to get the diameter

3 0
3 years ago
Read 2 more answers
Which statements are true?<br>(look at picture)​
Makovka662 [10]

Answer:

D is true, E is true, F is true

Step-by-step explanation:

Hello,

n is an odd number it means that n = 2a+1 where a is integer

A

n^2-1=(2a+1)^2-1=4a^2+4a+1-1=4a(a+1)

this is <u>not</u> an odd number

B

n(n-1)=(2a+1)2a

this is <u>not</u> an odd number

C

(n-1)^2=(2a+1-1)^2=4a^2

this is <u>not</u> an odd number

D

n^2+2=(2a+1)^2+2=4a^2+4a+1+2=4a^2+4a+3= 2(2a^2+2a+1)+1

so this is an odd number

E

n(n-2)=(2a+1)(2a-1)=4a^2-1=4a^2-2+1=2(2a^2-1)+1

so this is an odd number

F

(n-2)^2=(2a+1-2)^2=(2a-1)^2=4a^2-4a+1 = 2(2a^2-2a)+1

this is an odd number

hope this helps

7 0
3 years ago
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