Answer:
18.84 is the answer
Step-by-step explanation:
Can I please be marked as brainlist
Let f(x) = p(x)/q(x), where p and q are polynomials and reduced to lowest terms. (If p and q have a common factor, then they contribute removable discontinuities ('holes').)
Write this in cases:
(i) If deg p(x) ≤ deg q(x), then f(x) is a proper rational function, and lim(x→ ±∞) f(x) = constant.
If deg p(x) < deg q(x), then these limits equal 0, thus yielding the horizontal asymptote y = 0.
If deg p(x) = deg q(x), then these limits equal a/b, where a and b are the leading coefficients of p(x) and q(x), respectively. Hence, we have the horizontal asymptote y = a/b.
Note that there are no obliques asymptotes in this case. ------------- (ii) If deg p(x) > deg q(x), then f(x) is an improper rational function.
By long division, we can write f(x) = g(x) + r(x)/q(x), where g(x) and r(x) are polynomials and deg r(x) < deg q(x).
As in (i), note that lim(x→ ±∞) [f(x) - g(x)] = lim(x→ ±∞) r(x)/q(x) = 0. Hence, y = g(x) is an asymptote. (In particular, if deg g(x) = 1, then this is an oblique asymptote.)
This time, note that there are no horizontal asymptotes. ------------------ In summary, the degrees of p(x) and q(x) control which kind of asymptote we have.
I hope this helps!
Answer:
144 m^3
Step-by-step explanation:
Please find attached the image of the prisms
Volume of a triangular prism = area of the base x height of the prism
Area of the base = 1/2 ( base x height)
the two prisms are similar, thus, the dimensions of the bigger rectangle can be gotten from the ratio of the base of the smaller and bigger triangle
ratio of their dimensions = 6 / 1.5 = 4
the dimensions of the bigger triangle is 4 times that of the smaller triangle
height of the base of the prism = 1.5 x 4 = 6
Height of the prism = 2 x 4 = 8
Area of the base of the prism = (1/2) x 6 x 6 = 18 m^2
Volume of the prism = 18 x 8 = 144 m^3
Answer:
-51
Step-by-step explanation:
PEMDAS suggests you start with parenthesis
10+9•(-3)2-(7)
10-(27)2-(7)
10-54-7
-51
