Answer:
The surface area of the square pyramid is 
Step-by-step explanation:
we know that
The surface area of the square pyramid is equal to

where
B is the area of the base
P is the perimeter of the base
h is the height of the pyramid
<u>Find the area of the base B</u>

<u>Find the perimeter of the base P</u>

The height is 
substitute the values

Answer:
Step-by-step explanation:
The first step is to take p on both sides:

On the right hand side, cancel p and -p, since
. The equation will be:

Then, divide both sides of the equation by p*t:

On the right hand side, p*t can be cancelled:

Answer:
1.
The radius is given, so the radius is = 10
The radius is doubled to be a diameter, so (10 + 10) = 20 is your diameter
And to solve for circumference, your formula is;
C = 2πr
Where 'r' represents the radius, and 'π'(pi) is 22/7 or 3.14.
Plug in your values:-
C = 2πr
C = 2(3.14) x 10
C = 6.28 x 10
C = 62.8, so your circumference is 62.8.
2.
Your radius is half of your diameter, so,
D/2 = R
D = diameter
R = Radius
49/2 = 24.5 is your radius.
Your diameter is given, so the diameter is 49.
Use the formula we applied for circumference in our other problem;
C = 2πr
C = 2(3.14) x 24.5
C = 6.28 x 24.5
C = 153.86, so 153.86 is your circumference.
Answer:
Step-by-step explanation:
The first thing you ought to do is find out what you are trying to get. Desmos is an ideal program to do that if you don't have a graphing calculator. Just search for Desmos. It is pretty obvious once you get there. I've enclosed the graph to show you what it looks like.
Notice what happens around 5. The graph splits because effectively, you are dividing by 0 when you put 5 into the denominator. The question arises why doesn't the same thing happen at 0. It should: There is a discontinuity but it is very tiny. So the domain numbers that you should graph are
-1 0™ 1 2 3 4 4.5 4.8 5.3 5.4 6 7
™I wouldn't make 0 a part of this domain. But you can indicate with a dot where the graph goes.
I haven't filled in the range numbers. That's your job. All you have to do is fill in the table with points. Or you can put them on the graph that I have enclosed just to see where they points belong.
A graph is not to convey accuracy. It is to show the shape of function in question.
Answer:
You don't need to single out
to solve this question.
To solve:

So for the given interval 

(As confirmed by the attached graph)