The correct answer to the question
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Answer:
69.01 m
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you ...
Tan = Opposite/Adjacent
The tangent function is useful for problems like this. Let the height of the spire be represented by h. The distance (d) across the plaza from the first surveyor satisfies the relation ...
tan(50°) = (h -1.65)/d
Rearranging to solve for d, we have ...
d = (h -1.65)/tan(50°)
The distance across the plaza from the second surveyor satisfies the relation ...
tan(30°) = (101.65 -h)/d
Rearranging this, we have ...
d = (101.65 -h)/tan(30°)
Equating these expressions for d, we can solve for h.
(h -1.65)/tan(50°) = (101.65 -h)/tan(30°)
h(1/tan(50°) +1/tan(30°)) = 101.65/tan(30°) +1.65/tan(50°)
We can divide by the coefficient of h and simplify to get ...
h = (101.65·tan(50°) +1.65·tan(30°))/(tan(30°) +tan(50°))
h ≈ 69.0148 ≈ 69.01 . . . . meters
The tip of the spire is 69.01 m above the plaza.
Answer:
Part 1) The solution is the point (-2,0)
Part 2) The solutions are the points (-2,0) and (0,2)
Step-by-step explanation:
Part 1
we have
-----> equation A
---->
---> equation B
Solve the system by graphing
Remember that the solution of the system is the intersection point both graphs
using a graphing tool
The solution is the point (-2,0)
see the attached figure N 1
Part 2
we have
-----> equation A
----> equation B
Solve the system by graphing
Remember that the solution of the system are the intersection points both graphs
using a graphing tool
The solutions are the points (-2,0) and (0,2)
see the attached figure N 2
