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3 years ago

The correct answer to the question

Mathematics

1 answer:

Sladkaya [172]3 years ago

6 0

Set up a proportion.

3 black squares/9 total= x black squares/ 162 total

9*18=162
3*18=54

x=54

Final answer: B

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If you break up the number under the radical in the square root of 36 into two factors that are perfect squares, what are the tw

Pavel [41]

Answer: 4 and 9

Step-by-step explanation:

9 x 4 = 36

The square root of 9 is 3, so 9 is a perfect square.

The square root of 4 is 2, so 4 is a perfect square.

6 0

3 years ago

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Sandy is working with a carpenter to frame a house. They are using 8-foot-long boards, but each board must be cut to be 94.6 inc

shtirl [24]

7 foot is the answer...

7 0

3 years ago

10 3/9- 10 2/5 Im to lazy to do it please help me out.

coldgirl [10]

Answer:

$\boxed{ \ - \frac{3}{45} }$

Step-by-step explanation:

10 3/9 - 10 2/5

we need to convert mixed fractions to improper fractions

$10 \frac{3}{9} = \frac{10 \times 9 + 3}{9} = \frac{93}{9}$

$10 \frac{2}{5} = \frac{10 \times 5 + 2}{5} = \frac{52}{5}$

Now, we have 93/9 - 52/5

We need to equate the denominators, before subtracting them.

$\frac{93}{9} - \frac{52}{5} = \frac{93 \times 5}{45} - \frac{52 \times 9}{45}$

$\frac{465}{45} - \frac{468}{45}$

$\frac{ - 3}{45}$

$\boxed{ - \frac{3}{45} }$

The result of 10 3/9- 10 2/5 is - 3/45

8 0

2 years ago

For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?

Bond [772]

Given that $r=\theta$ , then $r'=1$

The slope of a tangent line in the polar coordinate is given by:

$m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}$

Thus, we have:

$m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}$

Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

$\sin\theta+\theta\cos\theta=0 \\ \\ \theta\cos\theta=-\sin\theta \\ \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta$

Therefore, the values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

θ = 0

θ = 2.02875783811043

θ = 4.91318043943488

Part B:

For vertical tangent lines, $\frac{1}{m} =0$

Thus, we have:

$\cos\theta-\theta\sin\theta=0 \\ \\ \Rightarrow\theta\sin\theta=\cos\theta \\ \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta$

Therefore, the values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:

θ = 4.91718592528713

3 0

3 years ago

Fill in the table using this function rule.

inysia [295]

Answer:

1, 2.2, 5.5, 10.2.

Step-by-step explanation: these are simplified to the nearest tenth

5 0

3 years ago

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