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mixer [17]
3 years ago
13

What is the answer to 8(8k-8)​

Mathematics
2 answers:
Agata [3.3K]3 years ago
4 0
64k-64








.................
levacccp [35]3 years ago
3 0

Answer

Step-by-step explanation:

1. 8(8k-8)

2. 64k-64

3. k= -1

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Formulate the situation as a system of inequalities. (Let x represent the number of dinghies the company can manufacture and y r
kirill [66]

Answer:

x (smallest to largest) = 0,45 ,55

y (smallest to largest) = 0,10,40

Step-by-step explanation:

(hours)        Dinghy Rowboat        Labor Available

Metal Work 2             3                       120

Painting         2              2                        110

Let x represent the number of dinghies the company can manufacture and y represent the number of rowboats.

So, total hours for metal work = 2x+3y

So, total hours for Painting = 2x+2y

So, equation becomes:

2x+3y\leq 120

2x+2y\leq 110

x\geq 0

y\geq 0

Plot the inequalities

Refer the attached figure

So, the vertices of the feasible region are (0,40),(45,10) and (55,0)

So, x values are 0 , 45 and 55

x represents the number of dinghies

So, x (smallest to largest) = 0,45 ,55

y values are 40,10,0

y represent the number of rowboats.

So, y (smallest to largest) = 0,10,40

3 0
3 years ago
2 Points<br>f(x) = x2. What is g(x)​
Korvikt [17]

Answer:

2 is the correct answer

8 0
3 years ago
Someone please help with this and explain your answer!!! I will give brainliest if correct!
Radda [10]

Answer:

the answer is a.

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A square has side length 3 units. What is the length of the diagonal?
ella [17]

9514 1404 393

Answer:

  C. 3√2 units

Step-by-step explanation:

The diagonal of a square is √2 times the side length. For a square with side length 3, the diagonal is 3√2.

__

If you like, you can see this using the Pythagorean theorem.

  d² = s² + s² . . . . . where d is the diagonal, and s is the side

  d² = 2s²

  d = √(2s²) = s√2

For s=3, ...

  d = 3√2

4 0
2 years ago
Twenty students from Sherman High School were accepted at Wallaby University. Of
nydimaria [60]

Answer:

Data provide convincing evidence of a difference in SAT scores  between students with and without a military scholarship is explained below in details.

Step-by-step explanation:

This is a quiz of 2 autonomous groups. The population model differences are not understood. it is a two-tailed examination. Let w be the index for scores of students with army research and o be the index for scores of students without army research.

Therefore, the population means would be μw and μo.

The irregular variable is x w - xo = variation in the sample mean records of students with military accomplishments and students without.

For students with military accomplishments,

n = 8

Mean = (850 + 925 + 980 + 1080 + 1200 + 1220 + 1240 + 1300)/8

Mean = 1099.375

Standard deviation = √(summation(x - mean)/n

Summation(x - mean) = (850 - 1099.375)^2 + (925 - 1099.375)^2 + (980 - 1099.375)^2 + (1080 - 1099.375)^2 + (1200 - 1099.375)^2 + (1220 - 1099.375)^2 + (1240 - 1099.375)^2 + (1300 -1099.375)^2 = 191921.875

Standard deviation = √(191921.875/8 = 154.89

For students without military scholarship,

n = 12

Mean = (820 + 850 + 980 + 1010 + 1020 + 1080 + 1100 + 1120 + 1120 + 1200 + 1220 + 1330)/12

Mean = 1073.83

Summation(x - mean) = (820 - 1073.83)^2 + (850 - 1073.83)^2 + (980 - 1073.83)^2 + (1010 - 1073.83)^2 + (1020 - 1073.83)^2 + (1080 - 1073.83)^2 + (1100 - 1073.83)^2 + (1120 - 1073.83)^2 + (1120 - 1073.83)^2 + (1200 - 1073.83)^2 + (1220 - 1073.83)^2 + (1330 - 1073.83)^2 = 238199.4268

Standard deviation = √(238199.4268/12 = 140.89

We would set up the hypothesis.

The null hypothesis is

H0 : μw = μo H0 : μw - μo = 0

The alternative hypothesis is

Ha : μw ≠ μo Ha : μw - μo ≠ 0

Since sample standard deviation is recognized, we would analyis the examination statistic by using the t examination. The formula is

(xw - xo)/√(sw²/nw + so²/no)

From the information given,

xw = 1099.375

xo = 1073.83

sw = 154.89

so = 140.89

nw = 8

no = 12

t = (1099.375 - 1073.83)/√(154.89²/8 + 140.89²/12)

t = 0.37

The formula for determining the degree of freedom is

df = [sw²/nw + so²/no]²/(1/nw - 1)(sw²/nw)² + (1/no - 1)(so²/no)²

df = [154.89²/8 + 140.89²/12]²/(1/8 - 1)(154.89²/8)² + (1/12 - 1)(140.89²/12)² = 21650688.37/1533492.15

df = 14

We would get the probability count from the t test calculator. It becomes

p value = 0.72

Since the level of importance of 0.05 < the p value of 0.72, we would not neglect the null hypothesis.

Therefore, these data do not present an acceptable indication of a difference in SAT scores between students with and without a military scholarship.

Part B

The formula for getting the confidence interval for the difference of two population means is expressed as

z = (xw - xo) ± z ×√(sw²/nw + so²/no)

For a 95% confidence interval, the z score is 1.96

xw - xo = 1099.375 - 1073.83 = 25.55

z√(sw²/nw + so²/no) = 1.96 × √(154.89²/8 + 140.89²/12) = 1.96 × √2998.86 + 1654.17)

= 133.7

The confidence interval is

25.55 ± 133.7

6 0
3 years ago
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