Answer:

Step-by-step explanation:
The given system of equations is presented as follows;

3·t - 6·s = 9
Making <em>t</em> the subject of both equations, gives;
In the first equation; t = (3 - s/2)/5
In the second equation; t = (9 + 6·s)/3
Equating both values of <em>t</em> to find the the values that satisfies both equations, gives;
(3 - s/2)/5 = (9 + 6·s)/3
3 × (3 - s/2) = 5 × (9 + 6·s)
9 - (3/2)·s = 45 + 30·s
45 - 9 = (30 + (3/2))·s
36 = (63/2)·s
s = 36/(63/2) = 8/7
t = (3 - s/2)/5
∴ t = (3 - (8/7)/2)/5 = 17/35
Therefore, the ordered pair is (8/7, 17/35)
1) 8^3/4 = 4th root (8^3) (top row, third one)
2) 7^2/3 = ∛7^2 (second row, third one)
3) 3^4/3 = ∛3^4 (second row, first one)
4) 25^3/4 = 4th root (25^3) (first row, first one)
5) 44^3/2 = √44^3 (third row, first one)
The pre image LMNO was translated using the rule (x + 5 , y + 7) to create the image L'M'N'O'.
L (-5 , -4) → (-5 + 5 , -4 + 7) → L' (0 , 3)
M (-7 , -1) → (-7 + 5 , -1 + 7) → M' (-2 , 6)
N (-1 , -1) → (-1 + 5 , -1 + 7) → N' (4 , 6)
O (-2 , -4) → (-2 + 5 , -4 + 7) → O' (3 , 3)
Hope this helps :)