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vaieri [72.5K]
4 years ago
15

How do you Solve 9/11 + 3/4

Mathematics
2 answers:
Mazyrski [523]4 years ago
6 0

Answer:

69

------

44

Step-by-step explanation:

Evgesh-ka [11]4 years ago
4 0

Answer:

144 is thee answer enjoy

Step-by-step explanation:

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Complete the equation <br> 9/4= ? ÷ by 4
Stells [14]

Answer:

9

Step-by-step explanation:

9/4 can be said as "9 divided by 4", so the ? is 9.

8 0
3 years ago
Sugar Rounds Donut Shop offers 2 free donuts with every 20 purchased donuts. Sweet Delights Donut Shop offers 3 free donuts with
statuscvo [17]

Answer:

there the same ratio because there both offering the same ratio of of there number

3x10=30 ratio : 10

2x10=20 ratio: 10

Step-by-step explanation:

8 0
3 years ago
Find the probability for the experiment of tossing a coin three times. Use the sample space S = {HHH, HHT, HTH, HTT, THH, THT, T
myrzilka [38]

Answer:

1) 0.375

2) 0.375

3) 0.5

4) 0.5

5) 0.875

6) 0.5                          

Step-by-step explanation:

We are given the following in the question:

Sample space, S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

1. The probability of getting exactly one tail

P(Exactly one tail)

Favorable outcomes ={HHT, HTH, THH}

\text{P(Exactly one tail)} = \dfrac{3}{8} = 0.375

2. The probability of getting exactly two tails

P(Exactly two tail)

Favorable outcomes ={ HTT,THT, TTH}

\text{P(Exactly two tail)} = \dfrac{3}{8} = 0.375

3. The probability of getting a head on the first toss

P(head on the first toss)

Favorable outcomes ={HHH, HHT, HTH, HTT}

\text{P(head on the first toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

4. The probability of getting a tail on the last toss

P(tail on the last toss)

Favorable outcomes ={HHT,HTT,THT,TTT}

\text{P(tail on the last toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

5. The probability of getting at least one head

P(at least one head)

Favorable outcomes ={HHH, HHT, HTH, HTT, THH, THT, TTH}

\text{P(at least one head)} = \dfrac{7}{8} = 0.875

6. The probability of getting at least two heads

P(Exactly one tail)

Favorable outcomes ={HHH, HHT, HTH,THH}

\text{P(Exactly one tail)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

3 0
3 years ago
 -453 divided by 15 = (simplest form)​
likoan [24]

Answer:

-453/15 = -30.2

8 0
3 years ago
Read 2 more answers
The pressure, P (in lbs/ft2 ), in a pipe varies over time. Five times an hour, the pressure oscillates from a low of 90 to a hig
Lunna [17]

P=160-70*cos(2π*(1/12)*t)

• Pressure in mathematics or physics is defined as force per unit area. The pressure exerted by a solid object which is resting on top of a solid surface is the weight divided by the area of the object . SI unit of force is Newton (N).

First, we find the amplitude by taking the difference between the peak values and dividing by two:

Amplitude=(230+90)/2=70

We can find the center value by either adding 70 to the minimum or subtracting 70 from the maximum:

90+70=160

230-70=160

This tells us that the Center Value=160

The frequency that we are operating at is given as:

f = 5/hour

so in minutes

f=5*(1/60)/minute=5/60=1/12 per minute

So, combining everything we get

P=160-70*cos(2π*(1/12)*t)

Learn more about Pressure here

brainly.com/question/26040104

#SPJ9

7 0
2 years ago
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