When a line of symmetry divides an image, every point on one side of the line has a corresponding point on the other side.

sdas [7]

Answer:

A

Step-by-step explanation:

With this question, its actually way easier than you think. If you want to find corresponding angles, you have to find a way to make the shapes overlap to be exactly the same. If they cannot be exactly the same, there will not be corresponding angles. For this, if you rotate quadrilateral 90 degrees counter-clockwise, you will see that the shapes look the same. Then you can just match up the angles that have the same degree measure (or just look the same for simplicity) and you have your answer. The answer is actually in the question too. ABCD=JKLM, but each letter is actually in the right place. A=J B=K C=L D=M.

Hope this helped! ^-^

7 0

3 years ago

Read 2 more answers

S^2t - 10 if s= -8 and t = 3/4

mart [117]

Answer:

-58

Step-by-step explanation:

input

-8^2(3/4)-10

simplify

-8^1.5-10

then solve

:)

3 0

3 years ago

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Im not sure how to explain my question in words so its in the file below-<br><br> ;-;

eimsori [14]

Answer:

C

Step-by-step explanation:

The arrow is pointing right is it is greater than which means that A and B are out. And for

D, -4 is not greater than -3 so D is also out which leaves only C

and -2 is greater than -3

4 0

3 years ago

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Seventy-two percent of the light aircraft that disappear while in flight in a certain country are subsequently discovered. Of th

Anton [14]

Answer:

a) 0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) 0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) 0.064 = 6.4% probability that 7 of them are discovered.

Step-by-step explanation:

For itens a and b, we use conditional probability.

For item c, we use the binomial distribution along with the conditional probability.

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

a) If it has an emergency locator, what is the probability that it will not be discovered?

Event A: Has an emergency locator

Event B: Not located.

Probability of having an emergency locator:

66% of 72%(Are discovered).

20% of 100 - 72 = 28%(not discovered). So

$P(A) = 0.66*0.72 + 0.2*0.28 = 0.5312$

Probability of having an emergency locator and not being discovered:

20% of 28%. So

$P(A cap B) = 0.2*0.28 = 0.056$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.056}{0.5312} = 0.105$

0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) If it does not have an emergency locator, what is the probability that it will be discovered?

Probability of not having an emergency locator:

0.5312 of having. So

$P(A) = 1 - 0.5312 = 0.4688$

Probability of not having an emergency locator and being discovered:

34% of 72%. So

$P(A \cap B) = 0.34*0.72 = 0.2448$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.2448}{0.4688} = 0.522$

0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) If we consider 10 light aircraft that disappeared in flight with an emergency recorder, what is the probability that 7 of them are discovered?

p is the probability of being discovered with the emergency recorder:

0.5312 probability of having the emergency recorder.

Probability of having the emergency recorder and being located:

66% of 72%. So

$P(A \cap B) = 0.66*0.72 = 0.4752$

Probability of being discovered, given that it has the emergency recorder:

$p = P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4752}{0.5312} = 0.8946$

This question asks for P(X = 7) when $n = 10$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 7) = C_{10,7}.(0.8946)^{7}.(0.1054)^{3} = 0.064$

0.064 = 6.4% probability that 7 of them are discovered.

8 0

2 years ago

What are the factors in the expression (a+b)12

BlackZzzverrR [31]

Solution:

1) Distribute
12a+12b

Done!

7 0

3 years ago