Let stadium 1 be the one on the left and stadium 2 the one on the right.
Angle above stadium 1 is 72.9° and the angle above stadium 2 is 34.1° using the angle property of alternate angles(because both the ground and the dotted line are parallel).
For the next part we need to use the trigonometric function of tangent.
As tan x = opposite / adjacent,
Tan 72.9°=1500/ adjacent ( the ground from O to stadium 1)
Therefore the adjacent is 1500/tan 72.9°= 461.46 m( to 5 s.f.)
Same for the next angle,
Tan 34.1°=1500/ adjacent ( the ground from O to stadium 2)
Therefore, the adjacent is 1500/tan 34.1° = 2215.49 m (to 5 s.f.)
Thus, the distance between both stadiums is 2215.49-461.46= 1754.03 m
Correcting the answer to whole number gives you 1754 m which is the option C.
Answer:
pretty sure D
Step-by-step explanation:
Total number of beads = 3 + 8 + 7 = 18. P(red) = total number of red/total number of beads = 3/18 = 1/6. P(blue) = total number of blue beads/total number of beads left after replacement = 8/17. P(black) = total number of black beads/total number of beads left after replacement = 7/16. Therefore P(red) = 1/6. P(blue) = 8/17. P(black) = 7/16.
(0,0) , (10,10) , (30,29) , (40, 38) , (50,45) , (60,51) , (70,59) , (80,61) , (90,65) , (100,79) , (110,70) (120,71)
Enter those coordinates into the table.
Answer:
16
Step-by-step explanation:
To start off this problem, we are given that the line AB is equal to the line CD. In addition to that, we are given that the line EF equally intersects line AB and line CD. This provides us proof that angle AGH is equivalent to angle DHG. From this information, we can solve this problem relatively easily.
Lets work with this equation:
Next, divide 80 by 5.
This means that x is equal to 16.
