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Oksanka [162]
3 years ago
12

9th grade math help me please and thank you sosomuch

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
7 0

Answer:

The system is consistent; it has one solution ⇒ D

Step-by-step explanation:

A consistent system of equations has at least one solution

  • The consistent independent system has exactly 1 solution
  • The consistent dependent system has infinitely many solutions

An inconsistent system has no solution

In the system of equations ax + by = c and dx + ey = f, if

  1. a = d, b = e, and c = f, then the system is consistent dependent and has infinitely many solutions
  2. a = d, b = e, and c ≠ f, then the system is inconsistent and has no solution
  3. a ≠ d, and/or b ≠ e, and/or c ≠ f, then the system is consistent independent and has exactly one solution

In the given system of equations

∵ -2y + 2x = 3 ⇒ (1)

∵ -5y + 5x = 12 ⇒ (2)

→ By comparing equations (1) and (2)

∵ -2 ≠ -5

∵ 2 ≠ 5

∵ 3 ≠ 12

→ By using the 3rd rule above

∴ The system is consistent independent and has exactly one solution

∴ The system is consistent; it has one solution

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xz_007 [3.2K]

Answer:

The solution of system of equation is (-2,0)

Step-by-step explanation:

Given system of equation are

Equation 1 :      2x+y=(-4)

Equation 2 :      y+\frac{1}{2}x=(-1)

To plot the equation of line, we need at least two points

For Equation 1 : 2x+y=(-4)

Let x=0

2x+y=(-4)

2(0)+y=(-4)

y=(-4)

Let x=1

2x+y=(-4)

2(1)+y=(-4)

y=(-6)

Therefore,

The required points for equation is (0,-4) and (1,-6)

For Equation 2 : y+\frac{1}{2}x=(-1)

Let x=0

y+\frac{1}{2}x=(-1)

y+\frac{1}{2}(0)=(-1)

y=(-1)

Let x=2

y+\frac{1}{2}x=(-1)

y+\frac{1}{2}(2)=(-1)

y=(-2)

The required points for equation is (0,-1) and (2,-2)

Now, plot the graph using this points

From the graph,

The red line is equation 1 and blue line is equation 2

Since. The point of intersection is solution of system of equations

The solution of system of equation is (-2,0)

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D

Step-by-step explanation:

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