Answer:
d. 128 cm^3
Step-by-step explanation:
to find the volume its length time width times heights; so 4 cm times 4 cm time 4 cm which is 64. Since the dice are the same size you add 64 cm^3 to 64 cm^3 to get 128 cm^3
Answer:
x = 2
Step-by-step explanation:
These equations are solved easily using a graphing calculator. The attachment shows the one solution is x=2.
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<h3>Squaring</h3>
The usual way to solve these algebraically is to isolate radicals and square the equation until the radicals go away. Then solve the resulting polynomial. Here, that results in a quadratic with two solutions. One of those is extraneous, as is often the case when this solution method is used.

The solutions to this equation are the values of x that make the factors zero: x=2 and x=-1. When we check these in the original equation, we find that x=-1 does not work. It is an extraneous solution.
x = -1: √(-1+2) +1 = √(3(-1)+3) ⇒ 1+1 = 0 . . . . not true
x = 2: √(2+2) +1 = √(3(2) +3) ⇒ 2 +1 = 3 . . . . true . . . x = 2 is the solution
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<h3>Substitution</h3>
Another way to solve this is using substitution for one of the radicals. We choose ...

Solutions to this equation are ...
u = 2, u = -1 . . . . . . the above restriction on u mean u=-1 is not a solution
The value of x is ...
x = u² -2 = 2² -2
x = 2 . . . . the solution to the equation
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<em>Additional comment</em>
Using substitution may be a little more work, as you have to solve for x in terms of the substituted variable. It still requires two squarings: one to find the value of x in terms of u, and another to eliminate the remaining radical. The advantage seems to be that the extraneous solution is made more obvious by the restriction on the value of u.
Answer:
In order to tell if these are congruent triangles we would need to know if angles Y and V were congruent, angles X and W are congruent or if segments XU and WU were congruent.
Step-by-step explanation:
Any of these would work because you can use two different methods to telling that these are congruent triangles.
The first method is called side-angle-side. In it you need two side lengths that are congruent with a congruent angle in the middle. Since we already know that the right angle in the middle is congruent, and we know YU and VU are congruent, we would just need to know the additional side to prove congruence.
The second method is called angle, angle side. In this we need to know that two angles in a row are congruent followed by a side. Since we know the middle angle is the same, knowing either other angles would give us this method as well.
First let's find the slope
Slope formula:

Given the two coordinates:
(-4,-7) (3,2)
x1,y1 x2,y2
Plug these numbers into the formula

In this case the mistake that was made was that the student wrote the slope negative instead of positive
Final answer:
<span>y-2=9/7(x-3)</span>