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murzikaleks [220]
2 years ago
9

During a thunderstorm, 600 millimeters of rain fell in 30 minutes. How fast did the rain fall, in millimeters per hour? NOOO BOT

S!!!!!!!!!!
Mathematics
2 answers:
nirvana33 [79]2 years ago
8 0

Answer:

1200 millimeters an hour

Step-by-step explanation:

30 minutes = 600 millimeters

1 hour= 1200 millimeters

Masja [62]2 years ago
7 0

Answer:

CAN YOU PLS RATE MY QUESTION GOOD I NEED POINTS

Step-by-step explanation:

PLS!!!!!!!!❤️

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I don’t get this someone answer this for me please show all work
Paraphin [41]

Answer:

5x=2x−4−2

Subtract 2 from −4 to get −6.

5x=2x−6

Subtract 2x from both sides.

5x−2x=−6

Combine 5x and −2x to get 3x.

3x=−6

Divide both sides by 3.

x= -6/3

​

 

Divide −6 by 3 to get −2.

x=−2

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
P2-16p+48=0 Please solve this math problem
Leni [432]

Answer:

( p - 4 ) ( p - 12 ) = 0

Step-by-step explanation:

To factor this equation, let's apply the quadratic formula.

p^2 - 16p + 48 = 0

Let a = 1, b = -16, c = 48

[-b +/- sqrt(b^2 - 4(a)(c))] / 2 (a)

[- (-16) +/- sqrt( (-16)^2 - 4(1)(48)) ] / 2 (1)

= [ 16 +/- sqrt( 256 - 192) ] / 2

= [ 16 +/- sqrt(64) ] / 2

= [16 +/- 8] / 2

p = (16 + 8) / 2 ; p = (16 - 8) / 2

p = 24 / 2  ; p = 8 / 2

p = 12  ;  p = 4

Hence, this equation factors into the following:

( p - 4 ) ( p - 12 ) = 0

Cheers.

8 0
3 years ago
Parallelograms ABDC and EFHG are similar. If side AC equals 4 units, side AB equals 16 units, and side EG equals 32 units, what
alexdok [17]
Remember that sides AC and EG will correspond. By finding the ratio of the lengths of these sides, we can find the length of EF.
The ratio of 4 to 16 simplifies to 1:4. This means that every side in ABDC is 1/4th of its corresponding side in EFHG. 16 times 4 is 64, so EF has a length of 64 units.
4 0
3 years ago
Three rational numbers between 5/31 and 6/31
Ludmilka [50]

Answer:

\dfrac{26}{155}, \dfrac{27}{155}, and \dfrac{28}{155}.

Step-by-step explanation:

What is a rational number? By definition, a rational number can be represented as the fraction of two integers.

The goal is to find three fractions in the form \dfrac{p}{q} between \dfrac{5}{31} and \dfrac{6}{31}.

\dfrac{5}{31} < \dfrac{p}{q} < \dfrac{6}{31}.

At this moment, there doesn't seems to be a number that could fit. The question is asking for three of these numbers. Multiple the numerator and the denominator by a number greater than three (e.g., five) to obtain

\dfrac{25}{155} < \dfrac{p}{q} < \dfrac{30}{155}.

Since p and q can be any integers, let q = 155.

\dfrac{25}{155} < \dfrac{p}{155} < \dfrac{30}{155}.

\implies 25 < p < 30.

Possible values of p are 26, 27, and 28. That corresponds to the fractions

\dfrac{26}{155}, \dfrac{27}{155}, and \dfrac{28}{155}.

These are all rational numbers for they are fractions of integers.

6 0
3 years ago
Please help fasttttttt
lord [1]

Answer:

40 or 50 i cant see, is it closer in size to L or I

Step-by-step explanation:

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