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2 years ago

If there are 60 min in a hour, 60 sec in min and 10 counts in a second how much is half of a second

Mathematics

1 answer:

Sedbober [7]2 years ago

8 0

There are 5 counts in half a second

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Is the relation a function 5,8 7,9 7,5 10,8

Tatiana [17]

No because the number 7 repeats no x-values can repeat.

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2 years ago

Evaluate the limit of lim/n->infinity 6n^2+5/3n^2

castortr0y [4]

we are given

$\lim_{n \to \infty} \frac{6n^2+5}{3n^2}$

we can see that

degree of numerator = degree of denominator =2

so, we can divide both numerator and denominator by n^2

and we get

$\lim_{n \to \infty} \frac{(6n^2+5)/n^2}{(3n^2/n^2)}$

$\lim_{n \to \infty} \frac{(6n^2/n^2)+(5/n^2)}{(3n^2/n^2)}$

now, we can simplify it

$\lim_{n \to \infty} \frac{6+(5/n^2)}{3}$

now, we can plug n=inf

$= \frac{6+(5/(\infty))}{3}$

$= \frac{6+0}{3}$

$= \frac{6}{3}$

$= 2$ ...............Answer

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2 years ago

Read 2 more answers

You are at a campus party where there are a total number of n people. The host asked everyone to put their phones in a bowl whil

kirill [66]

Answer:

1, $\frac{m}{n}$ , $\frac{1-m}{n}$ .

Step-by-step explanation:

probability = $\frac{Number of Possible Outcomes}{Total Outcomes}$

Total number of persons in the party = n

a) Pr ( every person gets their phone back) = Pr (each person picks his phone ) multiplied by number of person

= $\frac{1}{n}$ × n = 1.

No of first m persons to pick = m

No of last m persons to pick = 1 - m

b) Pr (first m persons to pick each gets their phones back) = $\frac{m}{n}$

c) Pr( first m persons get a phone belonging to last m persons) = $\frac{1-m}{n}$

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The answer is -10,368 ;)

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2 years ago

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love history [14]

Answer: 37

Step-by-step explanation:

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2 years ago