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saul85 [17]
3 years ago
15

Umm a little help pls?!

Mathematics
2 answers:
Vaselesa [24]3 years ago
7 0
The answer would be 117
k0ka [10]3 years ago
6 0

Answer:

116 degrees

Step-by-step explanation:

Supplementary Angles=180 degrees

64+x=180

180-64=116

116=116

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Imagine that you have an elementary school-age child and are researching childcare options. You find two that you like – one at
Rina8888 [55]

Answer:

a) Cost of the child-care center: y = 300 + 79x

Cost of the family-run childcare: y = 180 + 93x

Where x is the number of weeks.

b)  In the short-term, the family-run childcare will be cheapest because the charge for enrolling is less than for the child-care center.

c)The long term option (child-care center) becomes more cost-effective if you plan to enroll your child for more than 8.6 weeks.

Step-by-step explanation:

Hi there!

a)Let y be the cost of childcare. In the child-care center, the cost is 300 plus 79 per week. Let x be the number of weeks, then the cost function for the child-care center will be:

y = 300 + 79x

In the same way, the cost of the family-run childcare will be:

y = 180 + 93x

b) In the short-term, the family-run childcare will be cheapest because the charge for enrolling is less than for the child-care center. Let´s calculate the cost of both childcare options for low values of x:

Child-care center:

y = 300 + 79 x

x = 0, y = 300

x = 1, y = 379

x = 2, y = 458

x = 3, y = 537

x = 4, y = 616

Family-run:

y = 180 + 93x

x = 0, y = 180

x = 1, y = 273

x = 2, y = 366

x = 3, y = 459

x = 4, y = 552

c) We have to find the value of x for which the cost of the family-run childcare is greater than the cost of the child-care center:

cost family-run > child-care center

180 + 93x > 300 + 79 x

93x -79x >300 - 180

14x > 120

x > 120/14

x > 8.6

The long term option (child-care center) becomes more cost-effective if you plan to enroll your child for more than 8.6 weeks.

7 0
4 years ago
Can someone help me with this
Elenna [48]
Answer: x = 9

Explanation:
4 0
3 years ago
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Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin
sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x

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3 years ago
Which angles are corresponding angles?
Andrews [41]

Answer:

E) 1 and 5 B) 7 and 3

4 0
3 years ago
Read 2 more answers
What is the measure of
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Numbers? Letters? Objects?
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