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gizmo_the_mogwai [7]
2 years ago
6

How do you solve for X and A? ​

Mathematics
1 answer:
Ainat [17]2 years ago
4 0

9514 1404 393

Answer:

  3.  x = 10

  4.  a = 8

Step-by-step explanation:

A reasonably simple rule to remember for secants outside the circle or chords inside the circle: <em>the product of the lengths from the point of intersection of the lines to the points of intersection of the circle is the same for each line</em>.

When the external line is tangent to the circle, the two points of intersection of the line with the circle are the same: the point of tangency. Effectively, this means the length is squared.

__

3. For line QP, the product is 3(3+5) = 24.

For line QR, the product is 2(2+x). The rule above says these are equal:

  24 = 2(2+x)

  12 = 2+x . . . . . divide by 2

  10 = x . . . . . . . subtract 2

__

4. For line BC, the product is (a)(a) = a^2.

For line GC, the product is 4(12+4) = 64. The rule above says these are equal:

  a^2 = 64

  a = √64 . . . . take the square root

  a = 8

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<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ First identify and assign the variables:

q = number of quarters

d = number of dimes

This is what we know:

q + d = 22

A quarter is 25 cents and a dime is 10 cents

You can write this as:

0.25q + 0.1d = 3.40

Rearrange the first equation for d

d = 22 - q

Substitute this value into the other equation:

0.25q + 0.1(22 - q) = 3.40

Simplify:

0.25q + 2.2 - 0.1q = 3.40

0.15q + 2.2 = 3.4

Subtract 2.2 from both sides:

0.15q = 1.2

Divide both sides by 0.15:

q = 8

Substitute into the first equation:

8 + d = 22

d = 14

Therefore, there are 8 quarters and 14 dimes.

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➶ Hope This Helps You!

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