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gizmo_the_mogwai [7]
3 years ago
6

How do you solve for X and A? ​

Mathematics
1 answer:
Ainat [17]3 years ago
4 0

9514 1404 393

Answer:

  3.  x = 10

  4.  a = 8

Step-by-step explanation:

A reasonably simple rule to remember for secants outside the circle or chords inside the circle: <em>the product of the lengths from the point of intersection of the lines to the points of intersection of the circle is the same for each line</em>.

When the external line is tangent to the circle, the two points of intersection of the line with the circle are the same: the point of tangency. Effectively, this means the length is squared.

__

3. For line QP, the product is 3(3+5) = 24.

For line QR, the product is 2(2+x). The rule above says these are equal:

  24 = 2(2+x)

  12 = 2+x . . . . . divide by 2

  10 = x . . . . . . . subtract 2

__

4. For line BC, the product is (a)(a) = a^2.

For line GC, the product is 4(12+4) = 64. The rule above says these are equal:

  a^2 = 64

  a = √64 . . . . take the square root

  a = 8

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Gre4nikov [31]
If there are five stickers in 1 bag, and 2 of those are silver, 2/5 stickers are silver. 5*5=25. Then, you have 2*5=10, because 2/5 stickers were silver. Thus, I got to 10/25.
3 0
3 years ago
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zlopas [31]

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8 0
3 years ago
Need some help! Please be specific.
Gala2k [10]

Answer: 210 advanced tickets were sold. 130 same day tickets were sold.

Step-by-step explanation:

x= advanced tickets y=same day tickets

2x+3y=810 this equation represents the money

x+y=340 this equation represents the total number of tickets

x+y=340

<u>-x     -x</u>

y=-340-x             2x+3(340-x)=810               210+y=340

                           2x+1020-3x=810        <u>       -210     -210  </u>    

                           -x+1020=810                       y=130

                              <u>  -1020  -1020</u>

                                 <u>-x</u>=-<u>210</u>

                                 -1     -1

                                  x=210              

                             

3 0
2 years ago
What are the factors of x2 – 100?
Komok [63]

Answer:

(x+10)(x-10)

Step-by-step explanation:

Given : x^{2} -100

To Find : What are the factors of  x^{2} -100

Solution:

x^{2} -100

Since 100 =10^{2}

x^{2} -10^{2}

using property : a^{2} -b^{2} =(a+b)(a-b)

(x+10)(x-10)

Thus  the factors of x^{2} -100 are (x+10) and (x-10)


6 0
3 years ago
Read 2 more answers
Solve each equation. Leave the answer as an improper fraction. 16x2 = 49
pashok25 [27]
32x = 49
x = 49/32
Now since u said improper lets make 49/32 to mixed first, then improper
Lets divide 32 and 49 and we get 1 with a remainder of 17 
1 17/32
Now that's the mixed fraction, so now lets lastly make it improper 
1 * 32 + 17
--------------
32

 The answer is 49/32
8 0
4 years ago
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