Answer:
10
Step-by-step explanation:
for this you need to sub the value of -3 for x
Q(-3)=(-3)^2-(-3)-2
=9+3-2
=10
Sin0= y/r
X= -4 and r= 9 (radius is also the hypotenuse)
In quadrant II y is positive
X^2 +y^2 = r^2
-4^2 + y^2 = 9^2
16 + y^2 = 81
Y^2 = 81-16
Y^2 = 65
Y= sqrt65
Sin0= sqrt65/9
The given equation is

Here we have to solve for n. First we need to get rid of the denominators and for that we do cross multiplication .

Now we need to isolate n. And for that we need to get rid of 12, by dividing both sides by 12



And that's the required value of n .
Two equations
W*L=1260
3W+48=L
Solve
L=1260/W
3W+48=1260/W
3W^2+48W=1260
3W^2+48W-1260=0
Divide by 3
W^2+16W-420=0
Factor
(W-14) (W+30)
W=14
L=90