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Maru [420]
3 years ago
14

What is the probability of selecting an ace of diamonds from a deck of cards?

Mathematics
1 answer:
dybincka [34]3 years ago
6 0
4/52 i think if it is well your welcome if it’s not i’m sorry
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What is e+f/g in distributive property​
enot [183]

Answer:

e/g+f/g

Step-by-step explanation:

(e+f)/g  can be split up. e/g+f/g is equal to (e+f)/g so your answer is e/g +f/g

7 0
3 years ago
Solve the systems by elimination: <br><br> 8x-2y= -10<br> -4x+y= 5
Pachacha [2.7K]

Let's eliminate x.  To achieve this, mult. the 2nd equation by 2, obtaining

-8x + 2y = 10.  Now add this result to the first equation:

8x-2y= -10

-8x + 2y = 10

---------------------

        0

The two equations actually represent the same line.   Without an x- or a y-value, we cannot solve for the value of the other variable.  There are infinitely many solutions.

--------------------



4 0
3 years ago
NO LINKS PLEASE!
Nookie1986 [14]

Answer:

Set this up as a proportion.

54/n = 75/100

Now solve for n and finish from here.

Can i also have brain or a heart :)

8 0
3 years ago
Read 2 more answers
Please help thank you
iris [78.8K]
The question can be answered using the expression 1/3 * 3/7; is the questions C


8 0
3 years ago
In a batch of​ 8,000 clock radios 7​% are defective. A sample of 1313 clock radios is randomly selected without replacement from
PIT_PIT [208]

Answer: Probability that the entire batch will be rejected is 0.611.

Step-by-step explanation:

Since we have given that

Number of clock radios in a batch = 8000

Probability of defective clock radio = 7%

According to question, we have mentioned that A sample of 13 clock radios is randomly selected without replacement from the​ 8,000 and tested.

We will use "Binomial distribution":

here, n = 13 and

p (probability of success) = 7% = 0.07

so, we need to find that

P(the entire batch will be rejected)  = P(at least one of those test is defected)

So, it becomes,

P(at least one of those tested is defective) = 1 - P(none are defective)

So, P(none are defective ) is given by

(1-0.07)^{13}\\\\=0.93^{13}\\\\=0.389

So, P(at least one of those tested is defective) = 1 - P(none are defective)

                                                                             =  1 -  0.389

                                                                             =  0.611

Hence, Probability that the entire batch will be rejected is 0.611.

7 0
3 years ago
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