The two linear equations represented in system A as :
3 x + 2 y =3 -------(1)
- 2 x - 8 y = -1 ------(2)
(1) × 2 + (2) × 3 gives
⇒ 6 x + 4 y - 6 x - 24 y = 6 -3
⇒ - 20 y = 3
⇒ y = 
Putting the value of y in equation (1), we get
Two linear equation represented in system B is:
3. -x - 14 y =1
4. - 2 x - 8 y = -1
-2 ×Equation (3) + Equation (4)=
2 x +28 y- 2 x - 8 y= -2 -1
⇒ 20 y = -3
⇒y =
Putting the value of y in equation (3),we get
As Two system , that is system (A) and System (B) has same solution.
By looking at all the options , i found that Option (D) is correct. The two system will have the same solution because the first equation of System B is obtained by adding the first equation of System A to 2 times the second equation of System A.
No, this is not true every time. It depends on the conditions given.
For example-
Suppose we have a Box A with dimensions 10 x 10 x 1 and Box B with dimensions 5 x 5 x 5.
Box B has a surface area = 2(25+25+25) = 150 and a volume of 5*5*5= 125 cubic units
Box A has a larger surface area = 2(100+10+10) = 240 and a smaller volume = 10*10*1 = 100 cubic units
Similarly take an example of sphere.
Lets suppose the radius of the sphere is 2 cm
So, SA is 4πr² = 4*3.14*2*2 = 50.24 cm²
Volume of the sphere is = 4πr³ /3 = 33.50 cm³
Here also the SA is greater.
Speed=distance/time
average speed=(total distance)/(total time)
total distance=203+243=446
total time=3.5+4.5=8
average speed=(446)/(8)=55.75
answer is A
Answer:
1/4
Step-by-step explanation:
sorry for the messy work
With u = <-7, 6> and v = <-4, 17>, we have
u + 3v = <-7, 6> + 3 <-4, 17> = <-7, 6> + <-12, 51> = <-19, 57>
We want to find a vector w such that
u + 3v + w = <1, 0>
Subtract u + 3v from both sides to get
w = <1, 0> - (u + 3v) = <1, 0> - <-19, 57>
w = <20, -57>
