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harina [27]
3 years ago
6

two rival dry cleaners both advertise their prices. Store a prices are modeled by the expression 8x-5 where X is the number of

items brought in. Store bees prices are modeled by the expression 2(4x+6) , Where X is the number of items brought in. when do the two stores charge the same rate
Mathematics
1 answer:
avanturin [10]3 years ago
8 0

Answer:

The stores at no point in time will charge same rate ( their rates will always be different)

Step-by-step explanation:

To get the value of x that they charge same rate, we simply equate the value of rate in both;

thus;

8x-5 = 2(4x + 6)

8x-5 = 8x + 12

From what we have here, we can conclude that the equation has no solution

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Walt received a package that is 2 1/3 inches long, 6 3/4 inches high, and 8 1/2 inches wide. What is the surface area of the pac
grin007 [14]
Add whole numbers: 2 + 6 + 8 = 16
Add fractions:

= 1/3 + 3/4 + 1/2

= (8 + 18 + 12) ÷ 24

= 38/24 or 1 14/24 or simplified to 1 7/12

Total surface area = 16 + 1 7/12 or 17 7/12


5 0
3 years ago
Read 2 more answers
If the label of a can of yams were cut off and laid flat, which expression would give the area, A, of the label with the measure
Damm [24]
I think you are missing information to solve this problem.  Should there me an image attached to this question.

Either way, to solve for the label, the label would most likely me a rectangle when laid flat.

It's dimensions would be length x height.

Where height is most likely "h"
and
length is most likely the circumference (2πr)

Thus the possible answers are either:

B or C

I can't answer it until I see an image when more detail.

Hope this helps!

7 0
3 years ago
Test scores of the student in a school are normally distributed mean 85 standard deviation 3 points. What's the probability that
Mrrafil [7]

Answer:

The probability that a random selected student score is greater than 76 is \\ P(x>76) = 0.99865.

Step-by-step explanation:

The Normally distributed data are described by the normal distribution. This distribution is determined by two <em>parameters</em>, the <em>population mean</em> \\ \mu and the <em>population standard deviation</em> \\ \sigma.

To determine probabilities for the normal distribution, we can use <em>the standard normal distribution</em>, whose parameters' values are \\ \mu = 0 and \\ \sigma = 1. However, we need to "transform" the raw score, in this case <em>x</em> = 76, to a z-score. To achieve this we use the next formula:

\\ z = \frac{x - \mu}{\sigma} [1]

And for the latter, we have all the required information to obtain <em>z</em>. With this, we obtain a value that represent the distance from the population mean in standard deviations units.

<h3>The probability that a randomly selected student score is greater than 76</h3>

To obtain this probability, we can proceed as follows:

First: obtain the z-score for the raw score x = 76.

We know that:

\\ \mu = 85

\\ \sigma = 3

\\ x = 76

From equation [1], we have:

\\ z = \frac{76 - 85}{3}

Then

\\ z = \frac{-9}{3}

\\ z = -3

Second: Interpretation of the previous result.

In this case, the value is <em>three</em> (3) <em>standard deviations</em> <em>below</em> the population mean. In other words, the standard value for x = 76 is z = -3. So, we need to find P(x>76) or P(x>-3).

With this value of \\ z = -3, we can obtain this probability consulting <em>the cumulative standard normal distribution, </em>available in any Statistics book or on the internet.

Third: Determination of the probability P(x>76) or P(x>-3).

Most of the time, the values for the <em>cumulative standard normal distribution</em> are for positive values of z. Fortunately, since the normal distributions are <em>symmetrical</em>, we can find the probability of a negative z having into account that (for this case):

\\ P(z>-3) = 1 - P(z>3) = P(z

Then

Consulting a <em>cumulative standard normal table</em>, we have that the cumulative probability for a value below than three (3) standard deviations is:

\\ P(z

Thus, "the probability that a random selected student score is greater than 76" for this case (that is, \\ \mu = 85 and \\ \sigma = 3) is \\ P(x>76) = P(z>-3) = P(z.

As a conclusion, more than 99.865% of the values of this distribution are above (greater than) x = 76.

<em>We can see below a graph showing this probability.</em>

As a complement note, we can also say that:

\\ P(z3)

\\ P(z3)

Which is the case for the probability below z = -3 [P(z<-3)], a very low probability (and a very small area at the left of the distribution).

5 0
3 years ago
If 6xa=54 and b-a=14 what is axb
bagirrra123 [75]
6a=54 so a=54/6, a=9

b-a=14, and using a found above...

b-9=14

b=23,  so a=9 and b=23 so

ab=9(23)=207
6 0
3 years ago
Read 2 more answers
44.1 = 4.9p what does “p” equal
Talja [164]

Step 1: Flip the equation.

4.9p=44.1

Step 2: Divide both sides by 4.9.

4.9p= 44.1

4.9/4.9 = 44.1/4.9

p=9


3 0
3 years ago
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