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erik [133]
3 years ago
9

A college student completed some courses worth 3 credits and some courses worth 4 credits. The student earned a total of 59 cred

its after completing 18 courses.
How many courses worth 2 credits did the student complete?
Mathematics
1 answer:
quester [9]3 years ago
6 0

Answer:

He completed 13 courses worth 3 credits and 5 courses worth 4 credits.

Step-by-step explanation:

Let

Number of courses worth 3 credits = x

Number of courses worth 4 credits = y

1. The student completed a total of 18 courses, then

x+y=18

2. The student earned a total of 59 credits, he earned 3x on 3 credits' courses and 4y on 4 credits' courses, so

3x+4y=59

3. You get the system of two equations:

\left\{\begin{array}{l}x+y=18\\ \\3x+4y=59\end{array}\right.

From the first equation

x=18-y

Substitute it into the second equation:

3(18-y)+4y=59\\ \\54-3y+4y=59\\ \\4y-3y=59-54\\ \\y=5\\ \\x=18-5=13

He completed 13 courses worth 3 credits and 5 courses worth 4 credits.

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You have to start with thy x and the division than the minus and the plus

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3 years ago
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A line crosses through the points (0,2) and (-10, -16) Which of the following is the slope of the line?
Elodia [21]

Answer:

  9/5

Step-by-step explanation:

The slope between the two points can be found by ...

  m = (y2 -y1)/(x2 -x1)

  m = (-16-2)/(-10-0) = -18/-10

  m = 9/5

The slope of the line is 9/5. Perhaps this is a match to choice A.

3 0
3 years ago
What is the sum of the values of x and y that solves this system of equations?
motikmotik

Answer:

C) 3

Step-by-step explanation:

2x-y=3

-4x+2y=-6

4x+3y=11

-4x+2y=-6

4x+3y=11

5y=5

<u>y=1</u>

2x-y=3

2x-1=3

2x=4

<u>x=2</u>

2+1=<em><u>3</u></em>

6 0
3 years ago
Please answer both A. And B. Thank you!
const2013 [10]

Answer:

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Step-by-step explanation:

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3 years ago
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I WILL GIVE BRAINLIEST!! PLEASE HELPPP! The graph shows two lines, A and B:
gtnhenbr [62]

Answer:

(3, 4) is the solution to both lines A and B.

Step-by-step explanation:

First find the slope of each line by using the slope formula

Slope of A: -2 (passes through (2,6) and (5,0))

Slope of B: 2/3 (passes through (0,2) and (6,6))

Next, find the value of b by plugging each slope value and each corresponding x and y into the point slope equation y=mx+b

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(6)=-2(2)+b  I plugged in the point (2,6) but you can also use (5,0).  

6 = -4+b  Next solve for b

10=b, The equation of the line that passes through (2,6) and (5,0) is y=-2x+10

Slope B:

(2)=2/3(0)+b I plugged in the point (0,2) but you can also use (6,6).

2=b, The equation of the line that passes through (0,2) and (6,6) is

y=2/3x+2

Now you can solve for the system of equations using either substitution or elimination.  I will use substitution to first find the value of x.

y=-2x+10

y=2/3x+2

-2x+10=2/3x+2 Solve for x.

8=2 2/3x

x=3

Next plug in x to either of the equations to solve for y.

y=-2(3)+10

y=4, The solution to the system of equations is (3,4)  

To check, plug (3,4) into the equation y=2/3x+2

(4)=2/3(3)+2

4=2+2

4=4  This works therefore, (3, 4) is the solution to both lines A and B.

3 0
3 years ago
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