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emmainna [20.7K]
3 years ago
9

If x = –3 is the only x-intercept of the graph of a quadratic equation, which statement best describes the discriminant of the e

quation?
Mathematics
1 answer:
natita [175]3 years ago
7 0

Equations don't really have x intercepts, functions or curves do. They're also known as the zeros of the function.  When we set a function equal to zero we get an equation to solve, and the zeros of the function become the solutions or roots of the equation.

If a quadratic equation only has one root, that's a repeated root corresponding to a discriminant of zero.

In this example our equation is something like 2(x+3)^2=0, or expanded

2x^2+12x + 18 = 0

The discriminant d=b^2-4ac here is

d = 12^2 - 4(2)(18) = 0 \quad\checkmark


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What is the first step in solving the equation x2 – 16/25 = 0?
Keith_Richards [23]

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 

                     x^2-(16/25)=0 

Step by step solution :<span>Step  1  :</span> 16 Simplify —— 25 <span>Equation at the end of step  1  :</span><span><span> 16 (x2) - —— = 0 25 </span><span> Step  2  :</span></span>Rewriting the whole as an Equivalent Fraction :

<span> 2.1 </span>  Subtracting a fraction from a whole 

Rewrite the whole as a fraction using <span> 25 </span> as the denominator :

<span> x2 x2 • 25 x2 = —— = ——————— 1 25 </span>

<span>Equivalent fraction : </span>The fraction thus generated looks different but has the same value as the whole 

<span>Common denominator : </span>The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

<span> 2.2 </span>      Adding up the two equivalent fractions 
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

<span> x2 • 25 - (16) 25x2 - 16 —————————————— = ————————— 25 25 </span>Trying to factor as a Difference of Squares :

<span> 2.3 </span>     Factoring: <span> 25x2 - 16</span> 

Theory : A difference of two perfect squares, <span> A2 - B2  </span>can be factored into <span> (A+B) • (A-B)

</span>Proof :<span>  (A+B) • (A-B) =
         A2 - AB + BA - B2 =
         A2 <span>- AB + AB </span>- B2 = 
        <span> A2 - B2</span>

</span>Note : <span> <span>AB = BA </span></span>is the commutative property of multiplication. 

Note : <span> <span>- AB + AB </span></span>equals zero and is therefore eliminated from the expression.

Check :  25  is the square of  5 
Check : 16 is the square of 4
Check : <span> x2  </span>is the square of <span> x1 </span>

Factorization is :       (5x + 4)  •  (5x - 4) 

<span>Equation at the end of step  2  :</span> (5x + 4) • (5x - 4) ——————————————————— = 0 25 <span>Step  3  :</span>When a fraction equals zero :<span><span> 3.1 </span>   When a fraction equals zero ...</span>

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the <span>denominator, </span>Tiger multiplys both sides of the equation by the denominator.

Here's how:

(5x+4)•(5x-4) ————————————— • 25 = 0 • 25 25

Now, on the left hand side, the <span> 25 </span> cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
   (5x+4)  •  (5x-4)  = 0

Theory - Roots of a product :

<span> 3.2 </span>   A product of several terms equals zero.<span> 

 </span>When a product of two or more terms equals zero, then at least one of the terms must be zero.<span> 

 </span>We shall now solve each term = 0 separately<span> 

 </span>In other words, we are going to solve as many equations as there are terms in the product<span> 

 </span>Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

<span> 3.3 </span>     Solve  :    5x+4 = 0<span> 

 </span>Subtract  4  from both sides of the equation :<span> 
 </span>                     5x = -4 
Divide both sides of the equation by 5:
                     x = -4/5 = -0.800 

Solving a Single Variable Equation :

<span> 3.4 </span>     Solve  :    5x-4 = 0<span> 

 </span>Add  4  to both sides of the equation :<span> 
 </span>                     5x = 4 
Divide both sides of the equation by 5:
                     x = 4/5 = 0.800 

<span><span> x = 4/5 = 0.800
</span><span> x = -4/5 = -0.800
</span></span>
3 0
3 years ago
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Ket [755]

So 4x^2+-2x+-6 then multiply by 5 would be the Area of the entire rectangle using the formula A=bh

You'll get 4x^2  −  2x  −  6

5 0
3 years ago
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