If f(x)=2x^2+5 square root (x-2) what does f(3)=?

The number of boys in a club is 10 more than half the number of girls.

Sav [38]

Answer:

40 girls

Step By Step Explanation:

assume boys = y girls = x

y = 1/2x + 10

y = 30

30 = 1/2x + 10

1/2x = 20

x = 20 *2 = 40

girls is 40 boys is 30

6 0

2 years ago

Which is equivalent to 243 2/5 ? 3 6 9 12

NeTakaya

9 Good luckkkkkkkkkkkkkkkkkkkkkkkkkkkkk

3 0

2 years ago

Read 2 more answers

Could you please answer this precisely. Thank you!

OleMash [197]

The mathematical functions (equations) are matched to their graph line respectively as follows:

y = 960 - 78x: purple straight line.
y = 8·3^x: violet line curve that slopes to the left.
y = 960·(1/2)^x: green line curve that slopes to the right.

<h3>What is a linear function?</h3>

A linear function can be defined as a type of function whose equation is graphically represented by a straight line on the cartesian coordinate. Mathematically, a linear function is given by this equation:

y = mx ± c.

<h3>What is an exponential function?</h3>

An exponential function can be defined as a type of mathematical function whose values are generated by a constant that is raised to the power of the argument. Mathematically, an exponential function is represented by this formula:

f(x) = keˣ

Next, we would match each of the mathematical functions (equations) to their graph line respectively as follows:

y = 960 - 78x: purple straight line.
y = 8·3^x: violet line curve that slopes to the left.
y = 960·(1/2)^x: green line curve that slopes to the right.

Read more on graphs here: brainly.com/question/24298987

#SPJ1

3 0

1 year ago

. Given ????(5, −4) and T(−8,12):

damaskus [11]

Answer:

a) $y=\dfrac{13x}{16}-\dfrac{129}{16}$

b) $y = \dfrac{13x}{16}+ \dfrac{37}{2}$

Step-by-step explanation:

Given two points: $S(5,-4)$ and $T(-8,12)$

Since in both questions,a and b, we're asked to find lines that are perpendicular to ST. So, we'll do that first!

Perpendicular to ST:

the equation of any line is given by: $y = mx + c$ where, m is the slope(also known as gradient), and c is the y-intercept.

to find the perpendicular of ST <u>we first need to find the gradient of ST, using the gradient formula.</u>

$m = \dfrac{y_2 - y_1}{x_2 - x_1}$

the coordinates of S and T can be used here. (it doesn't matter if you choose them in any order: S can be either x_1 and y_1 or x_2 and y_2)

$m = \dfrac{12 - (-4)}{(-8) - 5}$

$m = \dfrac{-16}{13}$

to find the perpendicular of this gradient: we'll use:

$m_1m_2=-1$

both $m_1$ and $m_2$ denote slopes that are perpendicular to each other. So if $m_1 = \dfrac{12 - (-4)}{(-8) - 5}$ , then we can solve for $m_2$ for the slop of ther perpendicular!

$\left(\dfrac{-16}{13}\right)m_2=-1$

$m_2=\dfrac{13}{16}$ :: this is the slope of the perpendicular

a) Line through S and Perpendicular to ST

to find any equation of the line all we need is the slope $m$ and the points $(x,y)$ . And plug into the equation: $(y - y_1) = m(x-x_1)$

side note: you can also use the $y = mx + c$ to find the equation of the line. both of these equations are the same. but I prefer (and also recommend) to use the former equation since the value of 'c' comes out on its own.

$(y - y_1) = m(x-x_1)$

we have the slope of the perpendicular to ST i.e $m=\dfrac{13}{16}$

and the line should pass throught S as well, i.e $(5,-4)$ . Plugging all these values in the equation we'll get.

$(y - (-4)) = \dfrac{13}{16}(x-5)$

$y +4 = \dfrac{13x}{16}-\dfrac{65}{16}$

$y = \dfrac{13x}{16}-\dfrac{65}{16}-4$

$y=\dfrac{13x}{16}-\dfrac{129}{16}$

this is the equation of the line that is perpendicular to ST and passes through S

a) Line through T and Perpendicular to ST

we'll do the same thing for $T(-8,12)$

$(y - y_1) = m(x-x_1)$

$(y -12) = \dfrac{13}{16}(x+8)$

$y = \dfrac{13x}{16}+ \dfrac{104}{16}+12$

$y = \dfrac{13x}{16}+ \dfrac{37}{2}$

this is the equation of the line that is perpendicular to ST and passes through T

7 0

2 years ago

Patrice goes to fishers candy shop with the price of gummy candies modeled by the equation y=5/2x where x is the amount of gummy

icang [17]

Answer:

You need to put the question, but I'll try to help as much as I can without the question. y=5/2x, if you put the amount of gummy candy in lbs in the x's place, and you multiply the amount by 5/2, you will get the price.

Step-by-step explanation:

7 0

2 years ago