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3 years ago

Why 3 is correct answer

Mathematics

1 answer:

rosijanka [135]3 years ago

3 0

Because they meet in a right angle

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Find the interest due on $600 at 9.5% for 120 days.

KATRIN_1 [288]

Answer:

Interest= $ 18.73

Step-by-step explanation:

Given : $600 at 9.5% for 120 days

To find : Find the interest due

Solution :

Simple interest formula $I=P\times r\times t$

Principle(P)=$600 , rate(r)=9.5%=0.095 , time (t)= 120 days

In years, 1 year = 365 days

1 day = $\frac{1}{365}$ year

120 days = $\frac{120}{365}$ year

Put values in the formula

$I=P\times r\times t$

$I=600\times 0.095\times\frac{120}{365}$

$I=\frac{6840}{365}=18.73$

Therefore, Interest= $ 18.73

5 0

2 years ago

Read 2 more answers

60 % of 80 ASAP pls bruuh

Sati [7]

Answer:

Step-by-step explanation:

just ask siri

7 0

3 years ago

Differentiate with respect to X <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%5Cfrac%7Bcos2x%7D%7B1%20%2Bsin2x%20%7D%20

Mice21 [21]

Power and chain rule (where the power rule kicks in because $\sqrt x=x^{1/2}$ ):

$\left(\sqrt{\dfrac{\cos(2x)}{1+\sin(2x)}}\right)'=\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'$

Simplify the leading term as

$\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}$

Quotient rule:

$\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'=\dfrac{(1+\sin(2x))(\cos(2x))'-\cos(2x)(1+\sin(2x))'}{(1+\sin(2x))^2}$

Chain rule:

$(\cos(2x))'=-\sin(2x)(2x)'=-2\sin(2x)$

$(1+\sin(2x))'=\cos(2x)(2x)'=2\cos(2x)$

Put everything together and simplify:

$\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{(1+\sin(2x))(-2\sin(2x))-\cos(2x)(2\cos(2x))}{(1+\sin(2x))^2}$

$=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2\sin^2(2x)-2\cos^2(2x)}{(1+\sin(2x))^2}$

$=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2}{(1+\sin(2x))^2}$

$=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac{\sin(2x)+1}{(1+\sin(2x))^2}$

$=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac1{1+\sin(2x)}$

$=-\dfrac1{\sqrt{\cos(2x)}}\dfrac1{\sqrt{1+\sin(2x)}}$

$=\boxed{-\dfrac1{\sqrt{\cos(2x)(1+\sin(2x))}}}$

5 0

3 years ago

What is the solution to this equation? x + (- 14) = 4. (A) x = 10. (B) x = - 10. (C) x = - 18. (D) x = 18

Vika [28.1K]

First, you want to get x by itself on one side. We write the equation as $x-14=4$ . Since 14 is being subtracted from $x$ , we add it to both sides to cancel it out, $x-14+14=4+14$ or $x=18$ .

Your answer would be D.

4 0

3 years ago

Find the least common multiple of the set of numbers

stich3 [128]

Answer:

Step-by-step explanation:

plz mark brainliest :D

7 0

3 years ago