Answer:
97.94 is 83% of 118
Step-by-step explanation:
Let the missing number be x
97.94=83% of x
I.e, 97.94=83/100 × x
97.94=83x/100
Cross multipy 97.94/1=83x/100
We have, 97.94 × 100 = 83x × 1
9794=83x
Divide both sides by 83 to make x the subject of the formula.
9794/83=83x/83
118=x
Answer:
$34,000
Step-by-step explanation:
First they had 30,000
Then wrote off 40,000
So balance is 30,000 - 40,000 = -10,000
Now, they want 8% of 300,000 as uncollectible. So that would be
0.08 * 300,000 = 24,000
Thus, to bring the balance to 24,000 [balance is -10,000], how much would they need to add?? Let it be x:
-10,000 + x = 24,000
x = 24,000 + 10,000 = $34,000
The magnitude of YZ is 8.6
<u>Explanation:</u>
<u />
Y( -4, 12)
Z ( 1, 19)
Magnitude of YZ = ?
We know:
On substituting the value we get:
Thus, the magnitude of YZ is 8.6
Since both 4 and 6 are divisible by 2, it becomes 2/3<span />
Part A
Answers:
Mean = 5.7
Standard Deviation = 0.046
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The mean is given to us, which was 5.7, so there's no need to do any work there.
To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046
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Part B
The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67
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At 95% confidence, the critical value is z = 1.96 approximately
ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949
The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67
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Part C
Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.
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At 95% confidence, the critical value is z = 1.96 approximately
ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657
L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99
U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21
