From A draw the altitude AH intersecting BC in H
Let's prove that triangle ABH is congruent to triangle ACH
The above 2 triangles are right triangles due to the altitude AH
Angle B= Angle C (given)
Angle AHB = Angle AHC =90° (since AH is the altitude)
Then angle BAH = CAH (both complementary to B & C respectively
And AH is a common side
Now Tri. ABH = Tri. ACH because ASA, hence AB=AC
The volume of a cube is .
Hope this helps.
Y=5x-7 -3x-2y=-12 (2,3)
y=4x+3 y=-x-2 (-1,-1)
12x+8y=140 5 adults 10 children
12(5)+8(10)=140
60+80=140
Last one
hhhhhhhhhhbbbbbbbbbb
Answer:
Where is the graph?
Step-by-step explanation: