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tensa zangetsu [6.8K]
3 years ago
8

List all the possible rational zeros of p(x)=3x^3-3x^2+4x-12

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
3 0

Answer:

x = 3

x)=x^3-3x^2-4x+12  \\ 0 = 3x ^2 - 3x ^2 + 4x - 12 \\ 0 = 4x - 12 \\  - 4x =  - 12 \\  - x =  - 12 \div 4 \\ x = 3

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For f(x) = -5x + 4, what is the value of x for which f(x) = 20
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Answer:

- 3.2

Step-by-step explanation:

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x = 16 / - 5

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A. x = 2, y =6<br> B. x = 2, y =3<br> C. x =-2, y =3<br> D. x = -3, y =2
AlekseyPX

Answer:

The correct answer is A) x = 2 and y = 6

Step-by-step explanation:

In order to find the answer, we need to set the hypotenuses equal to each other. Then we can solve for y to get the equation.

y - 1 = x + 3

y = x + 4

Now we can do the same with the leg lengths.

y - 3 = 2x - 1

y = 2x + 2

Now that we have two equations, we can set them equal to each other to get the x value.

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Now that we have x, we can plug it into any equation to get the y value.

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5 0
3 years ago
Read 2 more answers
If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf
jonny [76]
With the curve C parameterized by

C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k

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\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt

where

\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt

The integral is then

\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt
=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t
=269
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4 years ago
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4 0
3 years ago
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